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Debora [2.8K]
3 years ago
7

(50 POINTS)Describe the transformation that maps the pre-image A to the image A'.

Mathematics
1 answer:
natima [27]3 years ago
3 0
You should really learn these, since later when you go into college they will also test you about graphs and such.

To do this, focus on one point of the pre-image A. Now, look at this point, and  see how it gets there to the actual image. In this case, it is translated 10 units to the right, and then 10 units down. If it was reflected across the y or x axis, the shape would be flipped, this pre-image was simply just translated to another place.

So, the answer you're looking for is <span>B) translated 10 units to right and then 10 units down </span>
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The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
What is the reason for each step in the solution of the equation?
user100 [1]

Answer in the attachment.

3 0
2 years ago
What is the initial value of the function represented by this table?
klemol [59]

Check the picture below.

7 0
3 years ago
The function Q(t)=Qoe^kt May be used to model radioactive decay. Q representing the quantity remaining after t years; k is the d
rewona [7]

Answer:

A. -[ln(0.5)/6,300]

Step-by-step explanation:

Done on apex, it is correct.

5 0
2 years ago
Read 2 more answers
If the vertex of a parabola is (9,6), what is the axis of symmetry?
zimovet [89]

Answer:

x=9 :)

Step-by-step explanation:

3 0
2 years ago
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