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Debora [2.8K]
3 years ago
7

(50 POINTS)Describe the transformation that maps the pre-image A to the image A'.

Mathematics
1 answer:
natima [27]3 years ago
3 0
You should really learn these, since later when you go into college they will also test you about graphs and such.

To do this, focus on one point of the pre-image A. Now, look at this point, and  see how it gets there to the actual image. In this case, it is translated 10 units to the right, and then 10 units down. If it was reflected across the y or x axis, the shape would be flipped, this pre-image was simply just translated to another place.

So, the answer you're looking for is <span>B) translated 10 units to right and then 10 units down </span>
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What is the slope-intercept form of the function described by this table?
Vikentia [17]
Y=5x - 3 Because the difference in the y values are 5, the rise is 5. That is the TOP of the slope. The difference in the x values is 1, that is the run or the BOTTOM of the slope. So m = 5/1. Using y = mx + b 2 = 5(1) + b -3 = b Therefore, y = 5x -3
8 0
3 years ago
Find the slope of the line passing through the points<br> (-6,-5) and (4,4)
marshall27 [118]

Answer:

\frac{9}{10}

Step-by-step explanation:

The slope formula is  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Here, x_{1} is -6, x_{2} is 4, y_{1} is -5, and y_{2} is 4.

m=\frac{4+5}{4+6}

m=\frac{9}{10}

So, the slope of the line passing through the points (-6,-5) and (4,4) is \frac{9}{10}.

3 0
3 years ago
Hello there!
jok3333 [9.3K]

Answer:

4. dy/dx = -2

8. dy/dx = 1/2 x^(-3/2)

10/ dy/dr = 4 pi r^2

Step-by-step explanation:

4.  y = -2x+7

dy/dx = -2(1)

dy/dx = -2

8.  y = 4 - x^-1/2

 dy/dx =  - (-1/2x^ (-1/2-1)

 dy/dx = 1/2 x^(-3/2)

10.  y = 4/3 pi r^3

dy/dr = 4/3 pi  (3r^2)

dy/dr = 4 pi r^2

7 0
3 years ago
y = c1 cos(5x) + c2 sin(5x) is a two-parameter family of solutions of the second-order DE y'' + 25y = 0. If possible, find a sol
TEA [102]

Answer:

y = 2cos5x-9/5sin5x

Step-by-step explanation:

Given the solution to the differential equation y'' + 25y = 0 to be

y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.

According to the boundary condition y(0) = 2, it means when x = 0, y = 2

On substituting;

2 = c1cos(5(0)) + c2sin(5(0))

2 = c1cos0+c2sin0

2 = c1 + 0

c1 = 2

Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given

y(x) = c1cos5x + c2sin5x

y'(x) = -5c1sin5x + 5c2cos5x

If y'(π) = 9, this means when x = π, y'(x) = 9

On substituting;

9 = -5c1sin5π + 5c2cos5π

9 = -5c1(0) + 5c2(-1)

9 = 0-5c2

-5c2 = 9

c2 = -9/5

Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation

y = c1 cos(5x) + c2 sin(5x) will give

y = 2cos5x-9/5sin5x

The final expression gives the required solution to the differential equation.

3 0
3 years ago
Examine the power.
Semenov [28]
Answer is 325 your welcome
6 0
3 years ago
Read 2 more answers
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