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3 years ago

What is nbr2 at the end of the program segment execution? nbr2 = 0 calc = 1 x = 7 while x >=3 calc = calc * x x = x - 2

Mathematics

1 answer:

Rashid [163]3 years ago

5 0

Answer:

nbr2 = 0

Step-by-step explanation:

Given

The following program segment

nbr2 = 0

calc = 1

x= 7

while x >=3:

calc = calc * x

x = x - 2

Required

The value of nbr2

In the first line, nbr2 was initialized to 0 i.e.

nbr2 = 0

From the second line of the program till the last, no operation was carried out on nbr2

This means that nbr2 will maintain its original value (which is 0)

Hence,

The value of nbr2 is 0

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What is the volume?

kogti [31]

Answer:

1282.82ft³

Step-by-step explanation:

To find the volume of the entire shape, we first need to find the volume of the cone and the cylinder separately.

Let's begin by getting the volume of the cylinder.

The formula to find the volume of a cylinder is:

$V=\pi r^{2}h$

r = 7 ft

h = 6 ft

Let's plug in our values into the formula.

$V=\pi (7)^{2}6$

$V=\pi (49)6$

$V=\pi (294)$

$V=923.63$ ft³

Now that we have the volume of our cylinder we need to find the volume of the cone.

The volume of the cone can be found by using the formula:

$V=\dfrac{1}{3}\pi r^{2}h$

Our variables for the cone are:

r = 7 ft

h = 7 ft

$V=\dfrac{1}{3}\pi (7)^{2}(7)$

$V=\dfrac{1}{3}\pi (49)(7)$

$V=\dfrac{1}{3}\pi (343)$

$V=\dfrac{1}{3}1077.57$

$V=359.19$ ft³

Now that we found both of the volumes of the two shapes, we can then simply get the sum of both volumes to get the total volume of the shape.

Total Volume = 923.63ft³ + 359.19ft³

Total Volume = 1282.82ft³

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3 years ago

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bulgar [2K]

Answer:

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Step-by-step explanation:

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If Bert had 3 cents more he would have twice as much as Georgia. If he had 4 cents less, he would have the same amount. How many

Ad libitum [116K]

Bert has 11 cents. Georgia has 7 cents.

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Any number raised to the power of zero is zero true or false

beks73 [17]

Answer: Any number times zero is zero, it can never equal something else.

Step-by-step explanation: My teacher taught me this before so i know :)

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The x-intercepts of the gravy of f (x)= x (x+1)(x-5)(x-7) are

Serhud [2]

"Of the gravy" lol

To find the x-intercepts, you make f(x) = 0 and solve for x by setting each factor equal to 0.

0 = x(x + 1)(x - 5)(x - 7)

x = 0

x + 1 = 0
x = - 1

x - 5 = 0
x = 5

x - 7 = 0
x = 7

Your x-intercepts are x = - 1, 0, 5, 7

OR

There are x-intercepts at (- 1, 0), (0, 0), (5, 0), and (7, 0).

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3 years ago