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lozanna [386]
4 years ago
5

Which of the following are major problems with fission reactors?

Physics
1 answer:
ValentinkaMS [17]4 years ago
3 0

Answer:

The correct answer is C: Disposal of radioactive waste.

Explanation:

During nuclear fission reactions, many intermediate radioisotopes are produced. For example, uranium releases different mass distribution isotopes and these isotopes emit radiations.

Most harmful isotopes for the environment are strontium and cesium because these have half-lives and an inclination of mixing in food chains.

When radioactive wastes are removed from nuclear reactors they flow towards the swimming pool and also have the tendency to isolate the short-lived isotopes from the environment.

Therefore, radioactive waste disposal has always remained a major problem

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Please answer this question first one to answer the right answer will be marked brainiest
Nataly_w [17]

Answer:  Force per unit area. Explanation: P = 25/20. P = 5/4 Pascal or 1.25 Pascal

Explanation: is this what you were looking for

8 0
3 years ago
When red light and green light shine on the same place on a piece of white paper, the spot appears t obe?
katen-ka-za [31]
When red light and green lights shine on the same place on a piece of white paper, the spot appears to be Yellow in color. Complementary colors are always located directly across from each other on the graphic. For example cyan is located across from red, magenta across from green, and yellow across from blue. When primary color mix the produce secondary colors , for example a red light and a green light will combine to form a yellow color. The production of various colors of light by the mixing of the three primary colors of light is known as color addition.
5 0
4 years ago
Read 2 more answers
A runner has a temperature of 40°c and is giving off heat at the rate of 50cal/s (a) What is the rate of heat loss in watts? (b)
Andrew [12]

Answer:

(a)  209 Watt

(b) 4482.8 seconds

Explanation:

(a) P = 50×4.18

Where P = rate of heat loss in watt

    P = 209 Watt

Applying,

Q = cm(t₁-t₂)................ Equation 1

Where Q = amount of heat given off, c = specific heat capacity capacity of human, m = mass of the person, t₁ and t₂ = initial and final temperature.

From the question,

Given: m = 90 kg, t₁ = 40°C, t₂ = 37°C

Constant: c = 3470 J/kg.K

Substtut these values into equation 1

Q = 90×3470(40-37)

Q = 936900 J

But,

P = Q/t.............. Equation 2

Where t = time

t = Q/P............ Equation 3

Given: P = 209 Watt, Q = 936900

Substitute into equation 3

t = 936900/209

t = 4482.8 seconds

5 0
3 years ago
Radiant heat makes it impossible to stand close to a hot lava flow. Calculate the rate of heat loss by radiation from 1.00 m^2 o
myrzilka [38]

Answer:

259.274 kW

Explanation:

Given:

Area of the lava, A = 1.00 m²

Temperature of the surrounding, T₁ = 30.0° C = 303 k

Temperature of the lava, T₂ = 1190° C = 1463 K

emissivity, e = 1

Now,

from the Stefan-Boltzmann law of radiation the rate of heat loss is given as,

u = σeA(T₂⁴ - T₁⁴)

where,

u = rate of heat loss

σ = Stefan-Boltzmann constant =  5.67 × 10⁻⁸ W/m²∙K⁴

on substituting the respective values, we get

u = 5.67 × 10⁻⁸ × 1 × 1 × (1463⁴ - 303⁴)

or

u = 259274.957 W

or

u = 259.274 kW

7 0
3 years ago
Electrons in an x-ray tube are accelerated through 144 kV and directed toward a target to produce x-rays. Calculate the power of
Katarina [22]

Answer:

Power of the electron beam in the x-ray tube is 2304 W

Explanation:

Given;

voltage of the electron beam in the x-ray tube, V =  144 kV = 144 x 10³ V

current of the electron beam in the x-ray tube, I = 16.0 mA = 16 x 10⁻³ A

Power is given as the product of voltage and current in a circuit.

Power of the electron beam in the x-ray tube, P = V x I

Power of the electron beam in the x-ray tube, P = 144 x 10³ V x 16 x 10⁻³ A

P = 2304 W

Therefore, power of the electron beam in the x-ray tube is 2304 W

7 0
3 years ago
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