The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.
<u>Given the following data:</u>
Charge = C.
Distance = 0.100 m.
<u>Scientific data:</u>
Coulomb's constant =
<h3>How to calculate the net force.</h3>
In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = F₁₃ + F₂₃
Mathematically, the electrostatic force between two (2) charges is given by this formula:
<u>Where:</u>
- r is the distance between two charges.
<u>Note:</u> d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.
For electrostatic force (F₁₃);
F₁₃ = 1.24 Newton.
For electrostatic force (F₂₃);
F₂₃ = 4.96 Newton.
Therefore, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = 1.24 + 4.96
F₃ = 6.2 Newton.
Read more on charges here: brainly.com/question/14372859
I’m pretty sure the answer is C. Any change of state or movement requires energy
Answer:
4.95 seconds
Explanation:
It is given that the speed of the cars are constant and not accelerating
The relative speed between the two cars will be the difference in their speeds
Converting to m/s
Time = Distance / Speed
Time it would take the faster car to cross the slower car is 4.95 seconds
Answer:
both an electric field and a magnetic field
Explanation:
Answer:
The new period is 16 s
Explanation:
The period of a simple pendulum is given by
Where is the period
is the length of the string
is the acceleration due to gravity
2π is constant
For the first experiment,
Then,
....... (1)
For the second experiment
Hence,
becomes
Then,
....... (2)
Since 2π is constant and
The same pendulum is used for the second experiment, then is also constant.
∴ is constant for both experiment.
Hence, we can equate equations (1) and (2) such that
Then,
Hence, the new period is 16 s