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VashaNatasha [74]
2 years ago
10

For which of the following conditions is it not appropriate to assume that the sampling distribution of the sample mean is appro

ximately normal?
A random sample of 8 taken from a normally distributed population

A random sample of 8 taken from a normally distributed population
A

A random sample of 50 taken from a normally distributed population

A random sample of 50 taken from a normally distributed population
B

A random sample of 10 taken from a population distribution that is skewed to the right

A random sample of 10 taken from a population distribution that is skewed to the right
C

A random sample of 75 taken from a population distribution that is skewed to the left

A random sample of 75 taken from a population distribution that is skewed to the left
D

A random sample of 100 taken from a population that is uniform
Mathematics
1 answer:
zhenek [66]2 years ago
8 0

Answer:

C

Step-by-step explanation:

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Use the ratio table to fine the unit rate with the specified units
Marianna [84]

Answer:

15.5 miles per gallon

Step-by-step explanation:

31/2=15.5 so its 15.5 miles per gallon or 31 miles with 2 gallons

5 0
2 years ago
I need help how do I slove this and how do I figure out the ratio. And could you provide a guide on how you go about finding the
bulgar [2K]

Answer:

<h3>Option C. 6 : 1 is the answer.. </h3>

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7 0
3 years ago
Julian saved between $ 30 and $ 52 over the summer. His friend Daniela saved twice as much. Let n represent the amount of money
maks197457 [2]

Y = (30 + 52) * 2

Y = (82) * 2

Y = 164

Daniela saved $164

3 0
3 years ago
) a, p and d are n×n matrices. check the true statements below:
BigorU [14]
A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).

b. True. Suppose \mathbf P is the matrix of the eigenvectors of \mathbf A, and \mathbf D is the diagonal matrix of the eigenvalues of \mathbf A:


\mathbf P=\begin{bmatrix}\mathbf v_1&\cdots&\mathbf v_n\end{bmatrix}

\mathbf D=\begin{bmatrix}\lambda_1&&\\&\ddots&\\&&\lambda_n\end{bmatrix}

Then

\mathbf{AP}=\begin{bmatrix}\mathbf{Av}_1&\cdots&\mathbf{Av}_n\end{bmatrix}=\begin{bmatrix}\lambda_1\mathbf v_1&\cdots&\lambda_n\mathbf v_n\end{bmatrix}=\mathbf{PD}

In other words, the columns of \mathbf{AP} are \mathbf{Av}_i, which are identically \lambda_i\mathbf v_i, and these are the columns of \mathbf{PD}.

c. False. A counterexample is the matrix

\begin{bmatrix}1&1\\0&1\end{bmatrix}

which is nonsingular, but it has only one eigenvalue.

d. False. Consider the matrix

\begin{bmatrix}0&1\\0&0\end{bmatrix}

with eigenvalue \lambda=0 and eigenvector \begin{bmatrix}k&0\end{bmatrix}^\top, where k\in\mathbb R. But the matrix can't be diagonalized.
7 0
3 years ago
A baker sells bread for $6 a loaf and rolls for $2 each. The baker needs to sell $66 worth of baked goods by
Ulleksa [173]

Answer:

the answer is 9

Step-by-step explanation:

the baker already sold 6 rolls (6*9)+ (2*6)=66                  54+12=66                                                                              

8 0
2 years ago
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