Answer:
b) 3(9) + 4 = 36 + 4 = 40
c) 3(0) + 4 = 0 + 4 = 4
d) 3(-3) + 4 = -9 + 4 = -5
e) 3(8) + 4 = 24 + 4 = 28
If that coordinate is reflected along the x-axis, the image will be (2,1).
Answer:
20
Step-by-step explanation:
Use the distance formula to determine the distance between the two points.
![\text{Distance}=\sqrt{(x_2=x_1)^2+(y_2-y1)^2}](https://tex.z-dn.net/?f=%5Ctext%7BDistance%7D%3D%5Csqrt%7B%28x_2%3Dx_1%29%5E2%2B%28y_2-y1%29%5E2%7D)
Substitute the actual values of the points into the distance formula.
![\sqrt{((-7)-5)^2+((-7)-9)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28%28-7%29-5%29%5E2%2B%28%28-7%29-9%29%5E2%7D)
Simplify.
⇒ Subtract 5 from 7.
![\sqrt{(-12)^2+((-7)-9)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-12%29%5E2%2B%28%28-7%29-9%29%5E2%7D)
⇒ Raise -12 to the power of 2.
![\sqrt{144+((-7)-9)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B144%2B%28%28-7%29-9%29%5E2%7D)
⇒ Subtract 9 from -7.
![\sqrt{144+(-16)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B144%2B%28-16%29%5E2%7D)
⇒ Raise -16 to the power of 2.
![\sqrt{144+256}](https://tex.z-dn.net/?f=%5Csqrt%7B144%2B256%7D)
⇒ Add 144 and 256.
![\sqrt{400}](https://tex.z-dn.net/?f=%5Csqrt%7B400%7D)
⇒ Rewrite 400 as 20².
![\sqrt{20^2}](https://tex.z-dn.net/?f=%5Csqrt%7B20%5E2%7D)
⇒ Pull terms out from under the radical, assuming positive real numbers.
20
The answer to your problem is -2.1.
Jason = 142 cm = 1.42 m
Amy = 137 cm = 1.37 m
Joseph = 1397 mm = 1.397 m
From shortest to tallest
I) Amy, Joseph, Jason