C is the circumcenter of triangle PQR. PC=3x+7, RC=5x-15, and QC=51-x What does QC=
1 answer:
Given:
C is the circumcenter of ΔPQR
PC = 3x + 7
RC = 5x - 15
QC = 51 - x
To find:
QC
Solution:
All vertices or a triangle are equidistant from its circumcenter.
Let us take .
Add 15 on both sides.
Add x on both sides.
Divide by 6 on both sides, we get
x = 11
Substitute x = 11 in QC.
QC = 51 - 11
= 40
Therefore QC = 40.
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A) 0.2076
B) 0.6786
C) 0.3214
Explanation:
A)
B) We find the probability that X=6, 7, or 8:
C) P(X≤5) = 1-P(X>5) = 1-0.6786 = 0.3214
B) 0.6786
C) 0.3214
Explanation:
A)
B) We find the probability that X=6, 7, or 8:
C) P(X≤5) = 1-P(X>5) = 1-0.6786 = 0.3214
We have been given a function . We are asked to find the amplitude, period and phase shift of the function
We can see that our given function is in form , where,
= Amplitude.
Period =
C = Horizontal shift,
D = Vertical shift.
We can see that value of a is 1, therefore, the amplitude of given function would be 1.
We can see that B is equal to 8, so we will get:
Therefore, the period of given function is .
Since the value of C is 1, therefore, horizontal shift is 1.
Since the value of D is 2, therefore, vertical shift would be 2.