Given:
C is the circumcenter of ΔPQR
PC = 3x + 7
RC = 5x - 15
QC = 51 - x
To find:
QC
Solution:
All vertices or a triangle are equidistant from its circumcenter.
Let us take .
Add 15 on both sides.
Add x on both sides.
Divide by 6 on both sides, we get
x = 11
Substitute x = 11 in QC.
QC = 51 - 11
= 40
Therefore QC = 40.
Answer:
Step-by-step explanation:
The window consists of a large square and 4 smaller triangles on the outside. The side length of this square is marked as 10, and therefore the area of this square is .
The area of a triangle is given by . Since the problem states that the overlapping squares are congruent, both legs of the triangle will be
and intersect at a
angle.
Thus, the sum of all four triangles is .
Therefore, the area of the window is:
The surface area of the triangular prism is 144 cm²
<u>Explanation:</u>
Given:
Base of the triangle = 4
Height of the triangle = 3
Hypotenuse of the triangle = 5
Length of the prism = 11
Surface area of the rectangular prism = ?
Surface area, A =
On substituting the value, we get:
Therefore, the surface area of the triangular prism is 144 cm²
Let , missing value(_)=A
As, it is given that ,
To convert the value of A into Radians,
360°=2 π Radians
So, missing value to the nearest hundredth= 1.26 Radians