All categories

2 years ago

1 - 4 + 6^2 ÷ ( 1 + 2 × 2 )

Mathematics

1 answer:

solniwko [45]2 years ago

4 0

Answer:

Step-by-step explanation:

957 6547

You might be interested in

30 points and gets a brainlest if correct

Sloan [31]

Answer:

9 : 25

Step-by-step explanation:

45 : 125 simplify =

8 0

2 years ago

What is the interquartile range of this data set? <br><br> Key: 1|5 means 15

antiseptic1488 [7]

Answer:

Step-by-step explanation:

IQR= Q3-Q1

Q3=50

Q1=40

50-40=10

Median=43

8 0

2 years ago

What is the least common multiple of 5 and 10

anyanavicka [17]

The least common multiple of 5 and 10 is 5. I hope this helps you.

6 0

2 years ago

Read 2 more answers

How do you get the answer

I am Lyosha [343]

Plug in -2 for a, 3 for b, and -5 for c. Then it'd be | (-3)^2 - 2(-2)(-5) +5 (3) |. Then, multiply everything to get | 9 -20 +15 |. Then, add/subtract to get | 4 |. Finally, take the absolute value and get 4.

5 0

3 years ago

Find the perimeter of a quadrilateral with vertices at C (-1, 2), D (-2, -1), E (2, -2), and F (1, 1). Round your answer to the

babymother [125]

Answer:

B 12.68

Step-by-step explanation:

you will need to find the distance between each segment-

so the length of DC, CF, FE, ED

$d=\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2} }$

DC:

D(-2,-1) C(-1,2)

$d=\sqrt{(-1--2)^{2} +(2--1)^{2} } \\d=\sqrt{1^{2}+3^{2} } \\d=\sqrt{10} =3.16$

CF:

C(-1,2) F(1,1)

$d=\sqrt{(1--1)^{2} +(1-2)^{2} } \\d=\sqrt{2^{2}+-1^{2} } \\d=\sqrt{4+1} \\d=\sqrt{x} 5=2.24$

F(1,1) E(2,-2)

$d=\sqrt{(2-1)^{2} +(-2-1)^{2} } \\d=\sqrt{1^{2} +(-3)^{2} } \\d=\sqrt{1+9} \\d=\sqrt{10}= 3.16$

E(2,-2) D(-2,-1)

$d=\sqrt{(-2-2)^{2} +(-1--2)^{2} } \\d=\sqrt{(-4)^{2}+1^{2} } \\d=\sqrt{16+1} \\d=\sqrt{17}= 4.12\\$

3.16+2.24+3.16+4.12= 12.68

4 0

2 years ago

1 - 4 + 6^2 ÷ ( 1 + 2 × 2 )​

1 - 4 + 6^2 ÷ ( 1 + 2 × 2 )