Which row of the input/output table is incorrect?

Mathematics

1 answer:

Dahasolnce [82]3 years ago

7 0

Row D because if you plug in 10 for x you get 17 not 15z

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What is the approximate radius of a sphere of volume 528 m³? round the answer to hundreth

makvit [3.9K]

$\\ \sf\longmapsto V=\dfrac{4}{3}πr^3$

$\\ \sf\longmapsto 528=\dfrac{4}{3}πr^3$

$\\ \sf\longmapsto \pi r^3=528\times \dfrac{3}{4}$

$\\ \sf\longmapsto πr^3=32(3)$

$\\ \sf\longmapsto \pi r^3=96$

$\\ \sf\longmapsto 3.14r^3=96$

$\\ \sf\longmapsto r^3=\dfrac{96}{3.14}$

$\\ \sf\longmapsto r^3=30.57$

$\\ \sf\longmapsto r=3.09m=3.1m$

5 0

3 years ago

Read 2 more answers

Vega wants to prove that the segment joining midpoints of two sides of a triangle is half the length of the third side. Select t

konstantin123 [22]

Answer:

The Answer is D : In triangle EFG△ , if EH=HF and EI=IG , then HI= 1/2 FG

FGH, I, equals, start fraction, 1, divided by, 2, end fraction, F, G.

Step-by-step explanation:

I Saw on Khan Academy

7 0

3 years ago

Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi

Vlad [161]

This problem is represented in the Figure below. So, we can find the components of each vector as follows:

$\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m$

$\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m$