The trigonometric identity can be used to solve for the height of the blue ladder that is leaning against the building is 
.
We have to determine
Which trigonometric identity can be used to solve for the height of the blue ladder that is leaning against the building?.
<h3>Trigonometric identity</h3>
Trigonometric Identities are the equalities that involve trigonometry functions and hold true for all the values of variables given in the equation.
Trig ratios help us calculate side lengths and interior angles of right triangles:
The trigonometric identity that can be used to solve for the height of the blue ladder is;
Hence, the trigonometric identity can be used to solve for the height of the blue ladder that is leaning against the building is .
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Answer:
625
600+20+5
Step-by-step explanation:
<em>Parenthesis</em>
<em>Exponent</em>
<em>Multiply</em>
<em>Divide</em>
<em>Add</em>
<em>Subtract</em>
<em>From left to right.</em>
<em>Do exponent first.</em>
<em>
</em>
<em>Standard form of 5^4 is: ⇒ 600+200+5</em>
<em>625 is the correct answer.</em>
<em>600+200+5 is the correct answer.</em>
Answer:
9/4 ÷ 7/2
9/4 × 2/7
9/14
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The sum of the first 8 terms is 2.51 to the nearest hundredth
Step-by-step explanation:
In the geometric sequence there is a constant ratio between each two consecutive terms
The formula of the sum of n terms of a geometric sequence is:
, where
- a is the first term
- r is the constant ratio between the consecutive terms
∵ The sequence is 6 , -5 , 25/6 , .............
∵ -5 ÷ 6 = 
∵ 
÷ -5 =
- There is a constant ratio between the consecutive terms
∴ The sequence is a geometric sequence
∵ The first term is 6
∴ a = 6
∵ The constant ratio is
∴ r =
∵ We need to find the sum of 8 terms
∴ n = 8
- Substitute the values of a, r and n in the rule above
∴ ![S_{8}=\frac{6[1-(\frac{-5}{6})^{8}]}{1-(\frac{-5}{6})}](https://tex.z-dn.net/?f=S_%7B8%7D%3D%5Cfrac%7B6%5B1-%28%5Cfrac%7B-5%7D%7B6%7D%29%5E%7B8%7D%5D%7D%7B1-%28%5Cfrac%7B-5%7D%7B6%7D%29%7D)
∴ 
- Round it to the nearest hundredth
∴ 
The sum of the first 8 terms is 2.51 to the nearest hundredth
Learn more:
You can learn more about the sequences in brainly.com/question/7221312
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