Hi could someone tell me how to solve this, you don’t even have to tell me the answer I’m just confused on this math and need he
lp with how to do it! (Will give 33 points (and POSSIBLY Brainliest if I’m able to)!
2 answers:
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Answer:
We need a sample of size at least 13.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
90% confidence interval: (0.438, 0.642).
The proportion estimate is the halfway point of these two bounds. So
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?
We need a sample of size at least n.
n is found when M = 0.08. So
Rounding up
We need a sample of size at least 13.