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sweet [91]
4 years ago
12

A short segment of a thin wire runs through a region of uniform magnetic field oriented perpendicular to the wire segment. If th

e magnitude of the magnetic field is 0.708~T T, and the magnetic force per unit length on the wire segment is 0.326~N/m N/m , calculate the current in the wire.

Physics
1 answer:
Nookie1986 [14]4 years ago
5 0

Explanation:

Below is an attachment containing the solution

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What is the gravitational potential energy of a two-particle system with masses 4.5 kg and 6.3 kg, if they are separated by 1.7
zepelin [54]

Answer:

7.41 x 10^-10 J

Explanation:

m = 4.5 kg

M = 6.3 kg

d = 1.7 m

The formula for the gravitational potential energy is given by

U = \frac{-GMm}{d}

Where, G is the Universal gravitational constant

G = 6.67 x 10^-11 Nm^2/kg^2

U = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{1.7}

U = - 1.112 x 10^-9 J

Now the separation is tripled, d' = 3 x d = 3 x 1.7 m = 5.1 m

Let the potential energy is U'

The formula for the gravitational potential energy is given by

U' = \frac{-GMm}{d'}

Where, G is the Universal gravitational constant

G = 6.67 x 10^-11 Nm^2/kg^2

U' = \frac{-6.67 \times 10^{-11}\times 6.3 \times 4.5}{5.1}

U' = - 3.71 x 10^-10 J

the work done is equal to the change in potential energy

W = U' - U

W = - 3.71 x 10^-10 + 1.112 x 10^-9

W = 7.41 x 10^-10 J

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4 years ago
What are the Cultural impacts from vehicles?
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Answer:

the use of non-renewable fuels, a dramatic increase in the rate of accidental death, the disconnection of local community, the decrease of local economy.

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How many mL beakers would be when seprating salt,sand,iron fillings,and beads
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Two identical carts are free to move along a straight frictionless track. At time t1, cart X is moving at 2.0 m/s when it collid
jarptica [38.1K]

Answer:

Explanation:

Using the law of conservation of momentum;

m_1 u_1+m_2u_2 = m_1v_1+m_2v_2

here;

There is a need for conservation of the total momentum that occurred before and after the collision.

So;

m_1 = mass of cart X

m_2 = mas 9f cart Y

u_1 = velocity of cart X (before collision)

u_2 = velocity of cart Y (before collision)

v_1 = velocity of cart X (after collision)

v_2 = velocity of cart Y (after collision)

So;

m(u_1+0) =(m_1v+m_2)v

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