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3 years ago

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If a spring requires 20 Newtons to be compressed a distance of 10 centimeters, what is the spring constant in N/m (newton meters

)?

1 answer:

Lady bird [3.3K]3 years ago

6 0

Answer:

20 N / 0.1 meters

Explanation:

10 centimetres is equal to 1 tenth of a meter or 0.1 meters.

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How may the desire for a perfect lawn related to environmental pollution

hodyreva [135]

Answer:

Lawns are extremely costly in many ways, including dollars spent on them, the deadly ... Using lawn equipment also significantly adds to noise pollution. ... to all of the environmental damages, including water pollution, caused by fracking. ... ONE's ambition is to remain unbiased and to provide a good

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4 years ago

Read 2 more answers

A sealed 26-m3 tank is filled with 6000 moles of oxygen gas (O2) at an initial temperature of 270 K. The gas is heated to a fina

TiliK225 [7]

Answer:

The final pressure of oxygen gas is 8.33 atm.

Explanation:

From the given data

V=26 m^3 or 26000 L

T1=270K

T2=440K

n1=6000 moles

R=0.0821 L.atm/molK

Now from the ideal gas equation

$P_2V_2=nRT_2\\P_2=\frac{nRT_2}{V_2}\\P_2=\frac{6000*0.0821*440}{26000}\\\\P_2=8.33 atm\\$

As the options given are not defined in which unit thus the final pressure of oxygen gas is 8.33 atm.

<em>*The options are provided for a different question where </em>

3 0

4 years ago

What is the escape velocity from a planet with a mass that is 10.8% Earths mass and a size that is 53% Earths radial size?

DENIUS [597]

The escape velocity from the planet is 5052 m/s

Explanation:

The formula to calculate the escape velocity from a planet is:

$v=\sqrt{\frac{2GM}{R}}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

M is the mass of the planet

R is the radius of the planet

For Earth,

$M_E=5.98\cdot 10^{24} kg$ is the mass

$R_E=6.37\cdot 10^6 m$ is the radius

Here we have a planet that:

- its mass is 10.8% of that of Earth, so

$M=0.108M_E$

- its radius is 53% of that of Earth, so

$R=0.53 R_E$

Substituting everything into the first equation, we find the escape velocity from this planet:

$v=\sqrt{\frac{2G(0.108M_E)}{0.53R_E}}=\sqrt{\frac{2(6.67\cdot 10^{-11})(0.108)(5.98\cdot 10^{24})}{(0.53)(6.37\cdot 10^6)}}=5052 m/s$

#LearnwithBrainly

4 0

3 years ago

A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is 4

bija089 [108]

Answer:

w = 0.55 rad / s

Explanation:

For this exercise let's use the conservation of angular momentum, let's write the moment in two moments

Initial

L₀ = r p + 0

L₀ = r mv

The first term is the angular momentum of the mass

Final

Lf = (I + m r²) w

Where I is the moment of inertia of the stool and the other term is the moment of inertia of the mass

L₀ = Lf

r mv = (I + m r²) w

w = m r v / (I + m r²)

Let's calculate

w = 2.0 0.45 3.0 / (4.5 + 2.0 0.45²)

w = 2.7 / 4.9

w = 0.55 rad / s

4 0

4 years ago

On a frictionless horizontal surface, a 1.50 kg mass traveling at 3.50 m/s collides with and sticks to a 3.00 kg mass that is in

My name is Ann [436]

Answer:

√ $\frac{3}{5} m$

Explanation:

Hope it helps!.

4 0

3 years ago