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CaHeK987 [17]
3 years ago
12

Solve by elimination -2x+2y=6 and 4x×2y=-5

Mathematics
1 answer:
Valentin [98]3 years ago
3 0

Answer:

x=-11/6, y=7/6. (-11/6, 7/6).

Step-by-step explanation:

-2x+2y=6

4x+2y=-5

-----------------

2(-2x+2y)=2(6)

4x+2y=-5

----------------------

-4x+4y=12

4x+2y=-5

----------------

6y=7

y=7/6

4x+2(7/6)=-5

4x+14/6=-5

4x=-5-14/6

4x=-30/6-14/6

4x=-44/6

x=(-44/6)/4

x=(-44/6)(1/4)

x=-44/24

simplify

x=-11/6

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Find cos(2*ABC) 100POINTS
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Answer:

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Step-by-step explanation:

<u>Trigonometric Identities</u>

\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

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  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

  • \cos(\angle ABC)=\dfrac{3}{5}
  • \sin(\angle ABC)=\dfrac{4}{5}

Therefore, using the trig identities and ratios:

\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}

7 0
2 years ago
Read 2 more answers
Genevieve wants to verify that One-fifth (5 x minus 20) minus one-half (4 x minus 8) is equivalent to Negative x. Which procedur
lora16 [44]

Answer:

The given expression is equivalent to -x

That is \frac{1}{5}(5x-20)-\frac{1}{2}(4x-8)=-x

Now Verified that the two expressions are equivalent

Step-by-step explanation:

Given that Genevieve wants to verify that One-fifth (5 x minus 20) minus one-half (4 x minus 8) is equivalent to Negative x

It can be written as below :

\frac{1}{5}(5x-20)-\frac{1}{2}(4x-8)=-x

Now we can verify the expression is equivalent or not :

Taking  LHS

\frac{1}{5}(5x-20)-\frac{1}{2}(4x-8)

=\frac{5x}{5}+\frac{-20}{5}-\frac{4x}{2}+\frac{8}{2} ( by using the distributive property )

=x-4-2x+4

=-x+0  ( adding the like terms )

=-x=RHS

Therefore LHS=RHS

Therefore the given expression is equivalent to -x

That is \frac{1}{5}(5x-20)-\frac{1}{2}(4x-8)=-x

Now Verified that the two expressions are equivalent

6 0
3 years ago
Read 2 more answers
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