The final temperature of copper is 155.43°C.
Step-by-step explanation:
The formula to apply is Q=m*Δt*c where ;
Q=heat energy, m=mass, c=specific heat capacity and Δt= change in temperature
Given that Q=54 calories , m=4.50 g and c=0.092 cal/g°C
In this question find Δt then ,the final temperature.
Δt=Q/m*c
Δt=54/4.50*0.092 =130.43°C
To find final temperature, apply the formula;
Δt=Final temperature - Initial temperature
130.43°C=Final temperature-25°C
130.43°C+25°C=Final temperature
155.43°C
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Specific Heat Capacity : brainly.com/question/12431744
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Answer: 5y + 4x = - 10
Step-by-step explanation:
Two lines are said to be perpendicular if the product of their gradients = -1.
If the gradient of the first line is
and the gradient of the second line is
, if the lines are perpendicular, them
x
= -1 , that is
= 
The equation of the line given is 5x - 4y = -3 , we need to write this equation in slope - intercept form in order to find the slope.
The equation in slope -intercept form is given as :
y =mx + c , where m is the slope and c is the y - intercept.
Writing the equation in this form , we have
5x - 4y = + 3
4y = 5x -+3
y = 5x/4 + 3/4
comparing with the equation y = mx + c , then
= 5/4
Which means that
= -4/5 and the line passes through the point ( -5 , 2 ).
Using the equation of line in slope - point form to find the equation of the line;
y -
= m ( x -
)
y - 2 = -4/5 ( x +5)
5(y - 2 ) = -4 ( x + 5 )
5y - 10 = -4x - 20
5y + 4x = - 10
So y^2 times 9^5 or
y*y means y times y so
y*y*9*9*9*9*9 or 59049y^2