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3 years ago

Which inequality represents the graph below s 75

Mathematics

2 answers:

lukranit [14]3 years ago

7 0

Answer:

It is s less than and equal to 75

Step-by-step explanation:

I say that because on 75 ther is a full circled dot instead of open dot.

telo118 [61]3 years ago

5 0

Answer:

Top Left

Step-by-step explanation:

Shaded circle means it will be Greater than or equal to or Less then or equal to. The answwers are less that or equal to 75 so s is less than or equal to 75

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At a fabric store, fabrics are sold by the yard. A dressmaker spent $36.35 on 4.25 yards of silk and cotton fabrics for a dress.

vaieri [72.5K]

Given:

The system of equations that represent the constraints for the given situation is

$x+y=4.25$

$16.90x+4y=36.35$

To find:

The solution of given system of equations.

Solution:

We have,

$x+y=4.25$ ...(i)

$16.90x+4y=36.35$ ...(ii)

Multiply equation (i) by 4.

$4x+4y=17$ ...(iii)

Subtracting (iii) from (ii), we get

$16.90x+4y-(4x+4y)=36.35-17$

$16.90x+4y-4x-4y=19.35$

$12.90x=19.35$

Divide both sides by 12.90.

$x=\dfrac{19.35}{12.90}$

$x=1.5$

Put this value in (i).

$1.5+y=4.25$

$y=4.25-1.5$

$y=2.75$

The solution of system of equations is x=1.5 and y=2.75. It means, the yards of silk are 1.5 and yards of cotton are 2.75.

5 0

3 years ago

Help me plzzzzzzzzz!!!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer: ( 12 , 9 )

Step-by-step explanation:

The formula for finding the coordinate of points when a line is externally divided in a given ratio is given by :

x = $\frac{p x_{2}+q x_{1}}{p+q}$

y = $\frac{p y_{2}+q y_{1}}{p+q}$

From the question

$x_{1}$ = 2

$x_{2}$ = ?

x = 4

$y_{1}$ = -1

$y_{2}$ = ?

y = 1

p = 1

q = 4

substituting the values into the formula ,we have

x = $\frac{p x_{2}+q x_{1}}{p+q}$

4 = $\frac{1(x_{2})+4(2) }{1+4}$

4 = $\frac{x_{2}+8}{5}$

$x_{2}$ + 8 = 20

$x_{2}$ = 12

Also

y = $\frac{p y_{2}+q y_{1}}{p+q}$

1 = $\frac{y_{2}+4(-1)}{5}$

$y_{2}$ - 4 = 5

$y_{2}$ = 9

Therefore , the end of the stencil is located at point ( 12 , 9 )

5 0

3 years ago

A new building in the shape of a square pyramid is to be constructed. The slant height will be five times the side length of the

Temka [501]

The area of the square pyramid building is the amount of space on it

The maximum base length of the building is 67.42 cm

<h3>How to determine the maximum side length?</h3>

The given parameters are:

Base = b

Slant height (l) = 5b

The lateral surface area is calculated using:

L = 2bl

So, we have:

L = 2 * b * 5b

Evaluate the product

L = 10b^2

The total surface area is calculated using:

T = L + b^2

So, we have:

T = 10b^2 + b^2

Evaluate the sum

T = 11b^2

The maximum surface area is 50,000 square feet

So, we have:

11b^2 = 50000

Divide both sides by 11

b^2 = 50000/11

Take the square root of both sides

b = 67.42

Hence, the maximum base length of the building is 67.42 cm

Read more about square pyramids at:

brainly.com/question/27226486

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3 years ago

Read 2 more answers

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melisa1 [442]

It's not showing the whole question

3 0

4 years ago

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A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$

Now, the probability of pulling three green marbles out with replacement is given by

$P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.$

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

4 0

3 years ago