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dedylja [7]
3 years ago
13

Compare the domains of the logarithmic function f(x) and the square root function g(x).

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

The domain of the function g(x) is greater than the domain of the function f(x).

Step-by-step explanation:

The diagram shows the logarithmic function f(x). The domain of this function is

x>-3

The domain of the square root function g(x)=\sqrt{x+3}+1 is

x+3\ge 0\\ \\x\ge -3

The domain of the function g(x) is greater than the domain of the function f(x), because the set x\ge -3 contains the set x>-3 ( (-3,\infty)\subset [-3,\infty)).

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