<span>a) How long will it take to roll "snake-eyes" (a pair of ones)?
P(a pair of ones) = 1/36
Therefore, it takes 36 rolls to roll "snake-eyes".
b) What is the probability of rolling a sum of 7 on the first roll?
P(a sum of 7) = 6/36 = 1/6
P(a sum of 7 on the first roll) = 1/6
c) What is the probability of rolling a sum of 7 on the fourth roll?
P(a sum of 7 on the fourth roll) = </span><span><span>(5/6)^3 * 1/6 = 125/1296</span>
d) What is the probability of rolling a sum of 7 by the fourth roll?
P(a sum of 7 by the fourth roll) = 1/6 + (5/6) * 1/6 + (5/6)^2 * 1/6 + (5/6)^3 * 1/6 = 1/6 + 5/36 + 25/216 + 125/1296 = 671/1296
e) What is the probability of it takin</span>g more than 10 rolls to roll the sum of 7?
P(more than 10 rolls to roll the sum of 7) = 1 - P(no sum of 7 in the first 10 rolls) = 1 - (5/6)^10 = 1 - 0.1615 = 0.8385
Answer:
a = 105 in²
Step-by-step explanation:
Front and back, triangles
a = 2 * (1/2)(5 * 6)
a = 30
Sides, squares
a = 3 * (5 * 5)
a = 75
Total
a = 30 + 75
a = 105 in²
Answer: I hope it helps :)
- x=6 , y=6√3
- x =23√3 , y=23
- u =12 , v= 6
- a =18√2 , b =18
- x = 13 , y= 13
Step-by-step explanation:
1.

2.

3.

4.

5.

Answer:
(4, 2)
Step-by-step explanation:
Start by combining the equations
2x + 2x = 4X
4y - 4y = 0
16 + 0 = 16
4x = 16
x = 4
Now that you have one variable plug it back in to one of the original equations
2(4) + 4y = 16
8 + 4y = 16
4y = 8
y = 2
(4, 2)
Answer:
80p + 48q - 8
Step-by-step explanation: