P = 2(L + W)
P = 14
W = L - 5
14 = 2(L + L - 5)
14 = 2(2L - 5)
14 = 4L - 10
14 + 10 = 4L
24 = 4L
24/4 = L
6 = L.......the length is 6 inches
W = L - 5
W = 6 - 5
W = 1 <=== the width is 1 inch
X=1/2-3y/4
and
x=10/3+2y/3
Answer:
The number is 91
Step-by-step explanation:
Let x be the ones place digit and y be the tens place digit,
Then the number would be 10y + x,
We have,
y - x = 8
Possible values of y and x = { (8, 0), (9, 1) }
∵ 0 is not the digit of the number,
Hence, y = 9 and x = 1
Therefore, required number = 10(9) + 1 = 90 + 1 = 91
Answer:
A circle is shown. Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N intersects the circle at point M. The length of P N is 32, the length of Q N is x, the length of L M is 22, and the length of M N is 14.
In the diagram, the length of the external portion of the secant segment PN is <u>X</u>
The length of the entire secant segment LN is <u>36</u>.
The value of x is <u>15.74</u>
Step-by-step explanation:
Snap
Jona_Fl16
Answer:
the answer should be 7a^3-4a^2-2a-87