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Pie
3 years ago
14

Graphing recorded data from a chart or table would be helpful for interpreting trends or patterns. Please select the best answer

from the choices provided
a. True
b. False
Mathematics
2 answers:
saul85 [17]3 years ago
6 0
True;
The data points the changes occurring at different points on the graph.
Fittoniya [83]3 years ago
5 0
The best answer to the question that is being presented above would be true. It is deemed true that graphing recorded data from a chart or table would be helpful for interpreting trends or patterns. This is because the graph shows the distribution of data and has an overall picture on how the data moves.
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INTELLIGENT STUDENT IN TRIG?.Ill give brainlest​
faltersainse [42]

Answers:

x = 6

y = 6*sqrt(2)

=======================

Explanation:

To find these values, you can use the general template of a 45-45-90 triangle or you can use trig ratios

tan(45) = 1

tan(angle) = opposite/adjacent

tan(45) = x/6

1 = x/6

6*1 = x

x = 6

-------

sin(45) = 1/sqrt(2)

sin(angle) = opposite/hypotenuse

sin(45) = 6/y

1/sqrt(2) = 6/y

1*y = sqrt(2)*6

y = 6*sqrt(2)

8 0
3 years ago
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s344n2d4d5 [400]
Answer is A because it’s just is
3 0
3 years ago
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Find the slope of the line
Phantasy [73]

Answer:

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Step-by-step explanation:

rise is 4

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3 years ago
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Jack went down 300 feet if jack started at 500 deet above sea level what is jack elevation now?.
e-lub [12.9K]

Answer:

200 ft above sea level

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8 0
4 years ago
The graph shows the distribution of the number of text messages young adults send per day. The distribution is approximately Nor
erik [133]

The percentage of young adults send between 128 and 158 text messages per day is; 34%

<h3>How to find the percentage from z-score?</h3>

The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.

We are given;

Sample mean; x' = 158

Population mean; μ = 128

standard deviation; σ = 30

We want to find the area under the curve from x = 248 to x = 158.

where x is the number of text messages sent per day.

To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;

z = (x - μ)/σ

z = (158 - 128)/30

z = 30/30

z = 1

This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.

From online p-value from z-score calculator, we have;

P-value = 0.34134 = 34%

Approximately 34% of the the population sends between 128 and 158 text messages per day.

Read more about p-value from z-score at; brainly.com/question/25638875

#SPJ1

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2 years ago
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