What is (x² + 7x + 6) divided by (x + 1)? X-6 - 7 X + 6 x + 7 need answer ASAP

The prism is completely filled with 1750 cubes that have edge length of 15 ft.

vladimir1956 [14]

It is 14 i got it on my test

5 0

2 years ago

Read 2 more answers

What is 8c squared + 7c

MariettaO [177]

(8c)^2+7c
(8c)^2=64c^2
so that..

64c^2+7c
factor out c
c(64c+7)

8 0

2 years ago

PLEASE HURRY. 55P WRONG ANSWERS GET REMOVED!!!!!!!

sertanlavr [38]

Answer:

1172. 08 in²

Step-by-step explanation:

Hi there !

A(prism) = 2(lw + lh + wh) - Ab(cylinder)

= 2(16*11 + 16*11 + 11*11) - πr²

= 2(176 + 176 + 121) - 3.14*16

= 2*473 - 50.4

= 946 - 50.24

= 895.76 in²

A(cylinder) = πr² + 2πr*h

= 3.14*16 + 2*3.14*4*9

= 50.24 + 226.08

= 276.32 in²

A(total) = 895.76in² + 276.32in² = 1172.08 in²

Good luck !

6 0

2 years ago

Find the odds for and the odds against the event rolling a fair die and getting a 1 comma a 2 comma or a 5.

IrinaVladis [17]

Answer:

1/2 for or against

Step-by-step explanation:

There is a six sided die so the chance of getting one side is 1/6.

To get the sum for 3 sides, just do 1/6 + 1/6 + 1/6 = 3/6 or 1/2.

4 0

2 years ago

(x +y)^5 Complete the polynomial operation

Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

$\left(x+y\right)^5$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=x,\:\:b=y$

$=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$

so expanding summation

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

solving

$\frac{5!}{0!\left(5-0\right)!}x^5y^0$

$=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5$

$=1\cdot \:1\cdot \:x^5$

$=x^5$

also solving

$=\frac{5!}{1!\left(5-1\right)!}x^4y$

$=\frac{5}{1!}x^4y$

$=\frac{5x^4y}{1}$

$=5x^4y$

similarly, the result of the remaining terms can be solved such as

$\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2$

$\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3$

$\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4$

$\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5$

so substituting all the solved results in the expression

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

$=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

Therefore,

$\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

6 0

2 years ago

What is (x² + 7x + 6) divided by (x + 1)?X-6- 7X + 6x + 7need answer ASAP​

What is (x² + 7x + 6) divided by (x + 1)?X-6- 7X + 6x + 7need answer ASAP