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zaharov [31]
3 years ago
5

How do you choose between mean and median as the best measure for the center of a distribution?

Mathematics
1 answer:
OverLord2011 [107]3 years ago
7 0
That would be the median I think...
You might be interested in
How do you find the area of this
zlopas [31]

Answer:

2345 units^2

Step-by-step explanation:

First, you can use Soh Cah Toa to find line c to be 36*sqrt(2). Furthermore, you can use the same equation to find the other sides to be both 65.15. To further solve, you just need to multiply 65.15 by 36 to get a final answer of 2,345.4 units^2

<em>Please Mark Brainliest if this helped!</em>

5 0
4 years ago
x+(x+3)+x^2=75 Please help........ Everyone is giving me answers i know arent true...
son4ous [18]

x + (x + 3) + x^{2} = 75

so you will add up all of the x 's but NOT the x^2

2x + 3 + x^{2} = 75

Rearrange to put the x^2 in front of 2x

x^{2} + 2x + 3 = 75

subtract the 75 from both sides

x^{2} + 2x - 72 = 0

8 0
3 years ago
Solve the following exponential equations.<br> 10^(3x−5) = 7^x
zalisa [80]

Answer:

x = 2.3202

Step-by-step explanation:

Given equation:

10^{(3x-5)} = 7^x

on taking log both sides, we get

\log(10^{(3x-5))} =\log(7^x)

now,

using the property of log function

log(aᵇ) = b × log(a)

therefore,

we get

(3x-5)log(10) = xlog(7)

now,

log(10) = 1

and

log(7) = 0.84509

thus,

( 3x - 5 ) × 1 = 0.84509x

or

3x - 0.84509x - 5 = 0

or

2.15491x = 5

or

x = 2.3202

4 0
3 years ago
En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?
Nonamiya [84]

Answer:

\displaystyle \tan A=\frac{4}{3}

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

6 0
3 years ago
Somebody please help me with this !!!
Damm [24]

Step-by-step explanation:

Case 1 :

3x + 2y = 6 \\ 4x + y = 2 \\ 3x = 6 - 2y \\ x =  \frac{6 - 2y}{3}  = \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) + y = 2 \\ 8 -  \frac{8y}{3}  + y = 2 \\  - 1.67y =  - 6 \\

y = 3.59 \\ x = 2 -  \frac{2y}{3}  \\x =  2 -  \frac{2 \times 3.59}{3}  \\  \\ x =  - 0.39

Case 2 :

3x + 2y = 6 \\ 4x  -  y = 2 \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) - y = 2 \\ 8 -  \frac{8y}{3}  - y = 2 \\   - 3.67y=  - 6 \\ y = 1.63

x = 2 -  \frac{2y}{3}  \\ x = 2 -  \frac{2 \times 1.63}{3}  \\ x = 2 - 1.087 \\ x = 0.913

7 0
3 years ago
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