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zaharov [31]
3 years ago
5

How do you choose between mean and median as the best measure for the center of a distribution?

Mathematics
1 answer:
OverLord2011 [107]3 years ago
7 0
That would be the median I think...
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for 9x + 25= 88, deena wrote the situation "i bought some shirts at the store for 9$ each and received a 25$ discount. my total
MrRissso [65]
Deena has included the discount on the wrong side of the equation.
3 0
3 years ago
Ashley one 129 pieces of gum playing our county fair at school she gave every student in her math class four pieces she has nine
viva [34]

Answer:

30

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%2F27%7D%20%3D%20-2%2F3" id="TexFormula1" title="\sqrt[3]{-8/27} = -2/3" al
sasho [114]
The equation is true because both sides are identical.
5 0
3 years ago
What is the value of c such that the line y=2x+3 is tangent to the parabola y=cx^2
satela [25.4K]

The value of c such that the line y = 2\cdot x + 3 is tangent to the parabola y = c\cdot x^{2} is -\frac{1}{3}.

If y = 2\cdot x + 3 is a line <em>tangent</em> to the parabola y = c\cdot x^{2}, then we must observe the following condition, that is, the slope of the line is equal to the <em>first</em> derivative of the parabola:

2\cdot c \cdot x = 2 (1)

Then, we have the following system of equations:

y = 2\cdot x + 3 (1)

y = c\cdot x^{2} (2)

c\cdot x = 1 (3)

Whose solution is shown below:

By (3):

c =\frac{1}{x}

(3) in (2):

y = x (4)

(4) in (1):

y = -3

x = -3

c = -\frac{1}{3}

The value of c such that the line y = 2\cdot x + 3 is tangent to the parabola y = c\cdot x^{2} is -\frac{1}{3}.

We kindly invite to check this question on tangent lines: brainly.com/question/13424370

3 0
3 years ago
Can anyone help me with the answer for number 4
klio [65]

Answer:

b

Step-by-step explanation:

Given K is the midpoint of JL, then

JK = KL ← substitute values

6x = 3x + 3 ( subtract 3x from both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Hence

JK = 6x = 6 × 1 = 6

KL = 3x + 3 = (3 × 1) + 3 = 3 + 3 = 6

JL = 6 + 6 = 12

7 0
4 years ago
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