Which result is a positive aspect of globalization?

Explain the appearance of earthworm in brief

andrew-mc [135]

Explanation:

An earthworm is a terrestrial invertebrate that belongs to the phylum Annelida. They exhibit a tube-within-a-tube body plan, are externally segmented with corresponding internal segmentation, and usually have setae on all segments. They occur worldwide where soil, water, and temperature allow

5 0

2 years ago

Name any four examples of economically marginalised group

ohaa [14]

Answer:

Here is a sample of the most common marginalized groups:

GLBT.

Senior citizens.

Racial/Cultural minorities.

Military Combat Veterans.

Persons of below average intelligence.

Hearing, visually, and Physically Challenged Persons.

Persons with a serious and Persistent Mental Illness (SPMI)

Persons with Cognitive Impairments.

6 0

3 years ago

UA Hamburger Hamlet (UAHH) places a daily order for its high-volume items (hamburger patties, buns, milk, and so on). UAHH count

Assoli18 [71]

Answer:

730 items

Explanation:

The objective of the given information is to determine the number of hamburgers UAHH should order for the following conditions:

Average daily demand 600

Standard deviation of demand 100

Desired service probability 99%

Hamburger inventory 800

The formula for a given order quantity in a fixed period of time can be expressed as :

$q = \overline d(L+T)+ z \sigma_{L+T}-I$

where;

$q$ = order quantity = ???

$\overline d$ = daily demand average = 600

L = lead time in days = 1

T = time taken = 1

z = no of standard deviation = ???

$\sigma_{L+T}$ = standard deviation of usage in lead time and time taken = ???

I = present inventory level = 800

$\sigma_{L+T}$ = $\sqrt 2$ × standard deviation of daily demand

$\sigma_{L+T}$ = $\sqrt{2} *100$

$\sigma_{L+T}$ = 1.4142 * 100

$\sigma_{L+T}$ = 141.42 items

From the Desired service probability 99% = 0.99; we can deduce the no of standard deviation by using the excel function (=NORMSINV (0.99))

z = 2.33

From $q = \overline d(L+T)+ z \sigma_{L+T}-I$

$q =600(1+1)+ 2.33*(141.42)-800$

$q =600(2)+ 2.33*(141.42)-800$

$q =1200+329.5086-800$

q = 729.5086 items

q ≅ 730 items

Therefore; the number of hamburgers UAHH should order from the following given conditions = 730 items

6 0

3 years ago

Operating data for Swifty Corporation are presented below. 2022 2021Sales revenue $830,700 $634,900 Cost of goods sold 529,000 4

Anastaziya [24]

Answer and Explanation:

The preparation of the vertical analysis is presented below:

Particulars Amount % Amount %

Sales $830,700 100 $634,900 100

Less:

Cost of goods sold $529,000 63.7 $415,000 65.4

Gross Profit $301,700 36.3 $219,900 34.5

Less:

Selling Expenses $124,700 15.0 $73,600 11.6

administrative expenses $78,800 9.5 $53,900 8.5

Total Operating

expenses $203,500 24.5 $127,500 20.9

Income before

income taxes $98,200 11.8 $92,400 14.5

Less:

Income tax expenses $33,500 4.0 $23,400 3.7

Net Income $64,700 7.8 $69,000 10.8

Working note

The percentage is like

= Items value ÷ sales × 100

Like for cost of goods sold

= $529,000 ÷ $830,700 × 100

= 63.68%

It is same applicable for other items also

7 0

3 years ago

Haskins Company employs material handling employees who move materials between production divisions at a labor cost of $360,000

Marianna [84]

Answer:

correct option is a. $36,000

Explanation:

given data

labor cost = $360,000

move material per year = 600,000 pounds

to find out

material handling cost

solution

we find here first Labor Cost per pound of material that is express as

Labor Cost per pound of material = Labor Cost ÷ Number of Pounds of material .......................1

Labor Cost per pound of material = $\frac{360000}{600000}$

Labor Cost per pound of material = $ .6 per pound of material

=360000/600000= $0.6 per pound of material

so we can say that 60000 pounds are moved in March so cost will be

60000 pounds are move cost = 60000 × $0.6

60000 pounds are move cost = $36000

so correct option is a. $36,000

7 0

3 years ago