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3 years ago

Will mark brainliest thank you!

Mathematics

1 answer:

Mashcka [7]3 years ago

4 0

Answer:

the answer is D 23/27 cars

Step-by-step explanation:

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One type of firework splits 5 times after it is fired into the air. The number of new bursts after each split can be modeled by

kherson [118]

Probably 5 because it only states 1 firework

5 0

3 years ago

Read 2 more answers

A box contains fifteen billiard balls, numbered 1 through 15. Anna draws a ball, records the number, and then returns it to the

Drupady [299]

The correct end part of the question says;

Find the probability of rolling an even number "then" an odd number

Answer:

Probability of rolling even, then odd = 56/225

Step-by-step explanation:

Now, the numbers are from 1 to 15.

Since we want find probability of even, then odd number, let's list all the even numbers first;

Even numbers from 1 to 15 are;

2, 4, 6, 8, 10, 12, 14

Odd numbers from 1 to 15 are;

1, 3, 5, 7, 9, 11, 13, 15

So, we have 7 even numbers and 8 odd numbers.

Probability of even is = 7/15

Probability of odd is = 8/15

Thus,probability of rolling even, then odd is;

P(even, then odd) = 7/15 x 8/15 = 56/225

6 0

3 years ago

Solve for m 13x - 10<br> M<br> N<br> 7x - 10

lisov135 [29]

Answer:

x = 10

Step-by-step explanation:

Given:

Arc LM = 13x - 10

Arc MN = 7x - 10

Required:

Solve for x

Solution:

Recall: half a circle = 180°

Therefore,

Arc LM + Arc MN = 180°

13x - 10 + 7x - 10 = 180

Add like terms

20x - 20 = 180

20x - 20 + 20 = 180 + 20

20x = 200

20x/20 = 200/20

x = 10

7 0

3 years ago

kim want to sell at least 500 worth of dessert each day at her Bakery she sells cakes for 8 each cupcake for 2 each if she solve

PtichkaEL [24]

20× 8 = 160

160 + 2x > or = 500
-160--------------- -160

2x > or = 340
÷2------------÷2

x > or = 170

She has to sell at least 170 cupcakes to make $500 in profit.

Hope this helps!

5 0

3 years ago

ITS TIMED PLEASE HELP

Lubov Fominskaja [6]

Answer:

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

$f(x)=\frac{1}{2}x^{2}-4x+5$

Convert to vertex form

$f(x)-5=\frac{1}{2}x^{2}-4x$

Factor the leading coefficient

$f(x)-5=\frac{1}{2}(x^{2}-8x)$

$f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x-4)^{2}$

$f(x)=\frac{1}{2}(x-4)^{2}-3$

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

5 0

3 years ago