Question

A campground has cabins that can each hold 28 campers there are 148 campers visiting the campground.how many cabins are full if 28 campers are in each cabin

Answer 1

Let the number of cabins be n.
We know that each cabin can hold up to 28 campers.

The second piece of information given is that there are 148 campers.
Now, we will divide 148 by 28 to get the number of cabins as follows:
n = 148/28 = 37/7 = 5.28

This means that we have five completely full cabins and one cabin which is not completely full.
number of campers in the partially full cabin = 148 - (28*5) = 8 campers

So,
We have 8 completely full cabins (each having 28 campers) and one cabin that has only 8 campers.

Answer 2

For this case, the first thing we must do is define variables.

We have then:

x: number of cabins

y: number of campers

We now write the equation that models the problem:

$y = 28x$

We know that there are 148 campers.

Therefore, substituting y = 148 in the given equation we have:

$148 = 28x$

From here, we clear the value of x:

$x = \frac{148}{28}\\x = 5.29$

Therefore, the number of full cabins is:

$x = 5$

Answer:

The number of full cabins is:

$x = 5$