Answer:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Step-by-step explanation:
Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.
We find mean = 11.015
Sample std deviation = 3.157
a) 
(Right tailed test)
Mean difference /std error = test statistic
p value =0.174
Since p >0.01, our alpha, fail to reject H0
Conclusion:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Answer:
D
Step-by-step explanation:
Solution:-
The standard sinusoidal waveform defined over the domain [ 0 , 2π ] is given as:
f ( x ) = sin ( w*x ± k ) ± b
Where,
w: The frequency of the cycle
k: The phase difference
b: The vertical shift of center line from origin
We are given that the function completes 2 cycles over the domain of [ 0 , 2π ]. The number of cycles of a sinusoidal wave is given by the frequency parameter ( w ).
We will plug in w = 2. No information is given regarding the phase difference ( k ) and the position of waveform from the origin. So we can set these parameters to zero. k = b = 0.
The resulting sinusoidal waveform can be expressed as:
f ( x ) = sin ( 2x ) ... Answer
Answer:
2
Step-by-step explanation:
Answer:
The equilibrium quantity is 26.4
Step-by-step explanation:
Given
Required
Determine the equilibrium quantity
First, we need to determine the equilibrium by equating Qd to Qs
i.e.
This gives:
Collect Like Terms
Solve for P
This is the equilibrium price.
Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:
<em>Hence, the equilibrium quantity is 26.4</em>
Plug in g equals -5 x -2 which equals 10 because 2 negatives are a positive then 10-6 equals 4
The anwser is 4
