Answer:
Container 
will have less label area than container 
by about 
.
Step-by-step explanation:
A rectangular sheet of paper can be rolled into a cylinder. Conversely, the lateral surface of a cylinder can be unrolled into a rectangle- without changing the area of that surface.
Indeed, the width of that rectangle will be the same as the height of the cylinder. On the other hand, the length of that rectangle should be exactly equal to the circumference of the circles on the top and the bottom of the cylinder. In other words, if a cylinder has a height of 
and a radius of 
at the top and the bottom, then its lateral surface can be unrolled into a rectangle of width and length 
.
Apply this reasoning to both cylinder 
and :
For cylinder , 
while 
. Therefore, when the lateral side of this cylinder is unrolled:
- The width of the rectangle will be
, while - The length of the rectangle will be
.
That corresponds to a lateral surface area of 
.
For cylinder , 
while 
. Similarly, when the lateral side of this cylinder is unrolled:
- The width of the rectangle will be
, while - The length of the rectangle will be
.
That corresponds to a lateral surface area of 
.
Therefore, the lateral surface area of cylinder is smaller than that of cylinder by 
.
Answer:
B
Step-by-step explanation:
The first quartile of his data is 60.
The median of his data is 82.
The first quartile Q1 is the median of the lower half of the data set. This means that about 25% of the numbers in the data set lie below Q1 and about 75% lie above Q1.
The median Q2 is the median of the data set. This means that about 50% of the numbers in the data set lie below Q2 and about 50% lie above Q2.
Between Q1 and Q2 lie exactly 25% of the numbers in the data set.
25% of 200 is exactly 50, so option B is true.
Answer:
Step-by-step explanation:
Answer: 1/5 of the total distance to his grandmothers house was traveled on Sunday
The total distance to to his grandmothers house is assumed to be 1
Marks family traveled 7/10 of the distance to his grandmothers house on Saturday. The remaining distance would
1 - 7/10 = 3 /10
They traveled 2/3 of the remaining distance on Sunday. This means that the distance that they travelled on Sunday is
2/3 × 3/10 = 2/10 = 1/5
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
Aritmetic increases by the same number
geometric has 1 number that each term is multiplied by to get the next term
4 to 9 is 5
9 to 13 is 4
not same difference
9/4=13/9?
81/36=52/36?
no
neither aritmetic nor geometric
