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3 years ago

Can I get some help on this please

Mathematics

1 answer:

solniwko [45]3 years ago

6 0

Sorry idk the answer

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D · 24 = -12 What does d equal?

Darya [45]

Answer: $d=-1/2$

Move all terms to the left

$d*24-(-12)=0$

Add all the numbers together, and all the variables

$d*24+12=0$

Multiply elements

$24d+12=0$

Move all terms containing d to the left, all other terms to the right

$24d=-12\\-12/24\\d=-1/2$

4 0

4 years ago

Read 2 more answers

Simplify -4(3-1)+2

nikdorinn [45]

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses.

-4(3 - 1) + 2

3 - 1 = 2

-4(2) + 2

We have no exponents so go on to multiplication

-4(2) + 2

-4 * 2 = -8

-8 + 2

No division so go to addition

-8 + 2

When adding a positive number with a negative number you will act as if you are subtracting the two numbers, then take the sign of the largest number (disregarding the signs). In this case the largest number is 8 and its sign is negative. Your answer will have a negative sign.

-6

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

4 years ago

Need help ASAP pls. :)

Troyanec [42]

Answer:

Step-by-step explanation:

because we just multiply the bottom equation by - and we eliminate 7y. now we have -2x=-10 to get x we divide -10 by -2 and get the answer

7 0

3 years ago

The probability of an event - picking teams. About (a) 10 kids are randomly grouped into an A team with five kids and a B team w

LuckyWell [14K]

Answer: The required probability is $\dfrac{4}{9}$

Step-by-step explanation:

Since we have given that

Number of kids = 10

Number of kids in Team A = 5

Number of kids in Team B = 5

There are three kids in the group, Alex and his two best friends Jose and Carl.

So, number of favourable outcome is given by

$2(\dfrac{8!}{3!\times 5!})$

Total number of outcomes is given by

$\dfrac{10!}{5!\times 5!}$

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

$\dfrac{2(\dfrac{8!}{5!\times 3!)}}{\dfrac{10!}{5!\times 5!}}\\\\=2\times \dfrac{8!}{3!}\times \dfrac{5!}{10!}\\\\=\dfrac{4}{9}$

Hence, the required probability is $\dfrac{4}{9}$

3 0

3 years ago

Pls help with this question

Anika [276]

Answer: A: I'm pretty sure

Step-by-step explanation: if you look at the graph the the 2 and 16 are the only lines where the 0 runs across and its also where the ticket prices are.

7 0

3 years ago