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Akimi4 [234]
3 years ago
9

What is 3/5 of $40? so hard!!!

Mathematics
2 answers:
MrRa [10]3 years ago
4 0
3/5 is .6 so 40*.6 is 24.
AlekseyPX3 years ago
3 0
24 is the answer you are looking for
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In the diagram (triangle) ABC = (triangle) PQR.
Paul [167]
B.
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3 years ago
A time in history was called the Stone Age, Why was it called this?
mestny [16]

Answer:

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8 0
3 years ago
Solve the Anti derivative.​
Alex Ar [27]

Answer:

\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C

General Formulas and Concepts:

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]:                                                                \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Trig Integration:                                                                                                           \displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx<u />

<u />

<u>Step 2: Integrate Pt. 1</u>

  1. [Integral] Factor fraction denominator:                                                         \displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx
  2. [Integral] Integration Property - Multiplied Constant:                                   \displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx

<u>Step 3: Identify Variables</u>

<em>Set up u-substitution for the arctan trig integration.</em>

\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx

<u>Step 4: Integrate Pt. 2</u>

  1. [Integral] Substitute u-du:                                                                               \displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du
  2. [Integral] Trig Integration:                                                                               \displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C
  3. [Integral] Simplify:                                                                                           \displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C
  4. [integral] Multiply:                                                                                           \displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C
  5. [Integral] Back-Substitute:                                                                             \displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0
2 years ago
What is the ratio for sine
Sphinxa [80]

Answer:

Blank 1: opposite

Blank 2: adjacent

Blank 3: opposite

Blank 4: adjacent

Step-by-step explanation:

There is a trigonometric acronym for this which is:

Soh Cah Toa

Soh means that sine is opposite over hypotenuse.

Cah means that cosine is adjacent over hypotenuse.

Toa means that tangent is opposite over adjacent.

Let me actually write these out as fractions:

sine is \frac{\text{opposite}}{\text{hypotenuse}}

cosine is \frac{\text{adjacent}}{\text{hypotenuse}}

tangent is \frac{\text{opposite}}{\text{adjacent}}

Blank 1: opposite

Blank 2: adjacent

Blank 3: opposite

Blank 4: adjacent

4 0
3 years ago
Calculate x Give your answer correct to 1 d.p. Х 35° 15 cm<br> it is a trigonometry question.​
OlgaM077 [116]

Here we are finding x, given the angle and adjacent side. To find x we will use the function cos as cos = a/h.

So let's do cos(35°) = 15cm / x

cos(35°) = 0.8 (1 dp)

x = 15 cm / cos(35°)

x = 18.3 cm (1 dp)

6 0
2 years ago
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