We know that rectangle EFGD has a width of 3. When we compare this 3 unit width to rectangle ABCD's width, we notice EFGC is 1/10 of ABCD. This means we are dividing by 10. ABCD's length happens to be 10. 10 divided by 10 is 1. EFGD's length is 1. Since we are solving perimeter, the expression would be 2l + 2w (w = 3, l = 1). 1 + 1 + 3 + 3 = 8 units.
Answer:
85.2 m²
Step-by-step explanation:
Perhaps one of the easiest ways to decompose this composite figure is to consider it as a rectangle with a triangle removed from it.
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The vertical dimension of the missing triangle is 8-4 = 4 m. The horizontal dimension of the missing triangle is 11.4 -8.4 = 3 m. The overall rectangle, including the missing triangle, is 11.4 m wide and 8 m high.
The area of the figure is ...
area = rectangle area - triangle area
= (11.4 m)(8 m) -1/2(4 m)(3 m) = 91.2 m² -6 m² = 85.2 m²
The area of the shape is 85.2 square meters.
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Additional comment
The area of a rectangle is the product of its length and width:
A = LW
The area of a triangle is half the product of its base and height:
A = 1/2bh
Answer:
The answer to your question is: 
Step-by-step explanation:
Data
27⁻²/³
Process

![\frac{1}{\sqrt[3]{27^{2}}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B27%5E%7B2%7D%7D%7D)
27 = 3³
= ![\frac{1}{\sqrt[3]{3^{3}^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B3%5E%7B3%7D%5E2%7D%20%7D)
= ![\frac{1}{\sqrt[3]{3^{6} } }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B3%5E%7B6%7D%20%7D%20%7D)
= 
= 
The answer is on the table.
3:24 and 5:40 are all equal to 1:8
7* 2 3/7
= 17/7* 7
= 17 (because 7 and 7 cancel out)
The final answer is 17~