<span>7x - 2 = 2y
7x = 2y + 2
so
</span>7x = 2y + 2<span>
3x = 2y - 1
----------------subtract
4x = 3
x = 3/4
</span>7x - 2 = 2y
7(3/4) - 2 = 2y
21/4 - 2 = 2y
21/4 - 8/4 = 2y
13/4 = 2y
so
y = 13/4 * 1/2
y = 13/8
answer
<span>(3/4, 13/8)</span>
We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
The equivalent expression of
is 
<h3>How to determine the equivalent expression?</h3>
The logarithmic expression is given as:

The law of logarithm states that:
log(a) - log(b) = log(a/b)
This means that the expression can be split as:

Hence, the equivalent expression of
is 
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