Answer:
![\sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Step-by-step explanation:
At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:
![\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%5Csqrt%20%5B4%5D%20%7Bx%5E2%7D%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%5Ccdot%20x%7D%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Alternatively, if you're allowed to use rational exponents, we can convert everything:
![\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20x%5E%7B%5Cfrac12%7D%20%5Ccdot%20x%5E%5Cfrac14%20%3D%20x%5E%7B%5Cfrac12%20%2B%5Cfrac14%7D%3D%20x%5E%7B%5Cfrac24%20%2B%5Cfrac14%7D%3D%20x%5E%5Cfrac34%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
The answer is D. The graph will be compressed vertically.
1/2f(x) means half of the y values of the original function making the graph shorter
The correct graph to the inequality is a number line with open dot at <em>negative 3</em> with shading to the left and an open dot at 6 with shading to the right. The correct option is the second option
<h3>Linear Inequalities </h3>
From the question, we are to determine the graph for the given compound inequality
The given compound inequality is
4p + 1 < −11 or 6p + 3 > 39
Solve the inequalities separately
4p + 1 < −11
4p < -11 - 1
4p < -12
p < -12/4
p < -3
OR
6p + 3 > 39
6p > 39 - 3
6p > 36
p > 36/6
p > 6
Thus,
p < -3 OR p > 6
Hence, the correct graph to the inequality is a number line with open dot at <em>negative 3</em> with shading to the left and an open dot at 6 with shading to the right. The correct option is the second option
Learn more on Linear Inequalities here: brainly.com/question/5994230
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The answer is C (SAS)
Explanation:
AC = EC
BC = DC
angle ACB = angle DCE (Vertically Opposite Angles)
Therefore, the triangles are congruent by the Side-Angle-Side congruency
