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3 years ago

Is (2, 2) a solution of the system y = x and x + 2y = 6?

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

8 0

Answer:

Yes.

Step-by-step explanation:

2=2, yes

2+2(2)=2+4=6, yes

Mariana [72]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

Substitute x = 2 and y = 2 into both equations and if both are true then (2, 2) is a solution of the system.

y = x, that is

2 = 2 ← True

x + 2y = 6, that is

2 + 2(2) = 2 + 4 = 6 ← True

Thus (2, 2) is a solution of the system

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Vesnalui [34]

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3 years ago

A ski resort claims that there is a 75% chance of snow on any given day in january and that snowfall happens independently from

creativ13 [48]

The mean exists at 3 and the standard deviation exists 0.87.

Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:

$$\mu_{X}=3, \sigma_{X}=0.87$

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The expected value of the binomial distribution exists:

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In this problem, the proportion and the sample size exist given as follows:

p = 0.75

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$$=\sqrt{4(0.75)(0.25)}=0.87$

The mean exists at 3 and the standard deviation exists 0.87.

To learn about the binomial distribution refer to:

brainly.com/question/24863377

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4 years ago

P->q is false and p is true.<br> q is<br> a.true<br> b.false

kirill [66]

Answer:

Choice b. $q$ has to be false.

Step-by-step explanation:

Consider the truth table of $p \implies q$ ( $p$ implies $q$ ).

$p$ is true and $q$ is true: $p \implies q$ would be true.
$p$ is true and $q$ is false: $p \implies q$ would be false.
$p$ is false and $q$ is true: $p \implies q$ would be true.
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The only combination where $p \implies q$ is false is when $p$ is true and $q$ is false. Hence, the $q\!$ here must be false.

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3 years ago

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stealth61 [152]

Answer:

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