Answer:
672 square inches
with area, multiply the side(s) by themselves for a single number, or their following numbers for more than 2 numbers.
Example
- 18in x 18in = 324 square inches
- 4in x 2in x 5in x 9in = 360 square inches
hope this helps!
Answer:
X = 15
Step-by-step explanation:
We can tell that the two sides that show the degrees are equal because of the arc. We can set up a simple equation:
x + 45 = 60
x = 15
Answer: y=-(1/8)x+(21/2)
Explanation:
The new equation’s slope needs to be perpendicular to y=8x-1
To get the new slope, we take the negative reciprocal of the slope from above
8 —> -1/8
Now we have y=-(1/8)x+b but it needs to pass through (4,10), so we need to find the value of b that makes this possible.
Since (4,10) is in the form of (x,y) we can plug in these values into the new equation to solve for b:
y=-(1/8)x+b
10=-(1/8)4+b
10=(-1/2)+b
b=(21/2)
Now put b back into the new equation
y=-(1/8)x+b
y=-(1/8)x+(21/2)
Answer:
72 feet from the shorter pole
Step-by-step explanation:
The anchor point that minimizes the total wire length is one that divides the distance between the poles in the same proportion as the pole heights. That is, the two created triangles will be similar.
The shorter pole height as a fraction of the total pole height is ...
18/(18+24) = 3/7
so the anchor distance from the shorter pole as a fraction of the total distance between poles will be the same:
d/168 = 3/7
d = 168·(3/7) = 72
The wire should be anchored 72 feet from the 18 ft pole.
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<em>Comment on the problem</em>
This is equivalent to asking, "where do I place a mirror on the ground so I can see the top of the other pole by looking in the mirror from the top of one pole?" Such a question is answered by reflecting one pole across the plane of the ground and drawing a straight line from its image location to the top of the other pole. Where the line intersects the plane of the ground is where the mirror (or anchor point) should be placed. The "similar triangle" description above is essentially the same approach.
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Alternatively, you can write an equation for the length (L) of the wire as a function of the location of the anchor point:
L = √(18²+x²) + √(24² +(168-x)²)
and then differentiate with respect to x and find the value that makes the derivative zero. That seems much more complicated and error-prone, but it gives the same answer.
The answer is 260 have a good day.
I love it when people ask me these questions.