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velikii [3]
3 years ago
9

A cell phone company charges a monthly fee plus $0.25$0.25 for each text message. The monthly fee is $30.00$30.00 and you owe $5

9.50$59.50. Write and solve an equation to find how many text messages xx you had.An equation is
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0
<span>Equation: $59.50 - $30.00 = $0.25X =$29.50 = $0.25X =$29.50/$0.25 = X = 118 text messages used Explanation - First you take the total bill less the monthly fee of $30 to get $29.50. This amount represents the amount of the bill generated by the text messages you used. Then you divide this amount by $0.25 to get the total number of text, which is 118.</span>
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A data analyst has spreadsheets numbered
algol [13]

Answer:

\frac{2}{9}

Step-by-step explanation:

{\textrm}{Total number of objects here} = 9

(2 spreadsheets, 3 databases and 4 presentations,

{\textrm}({Total} = 2+3+4 = 9)

{\textrm}{No. of databases with an odd number} = 2 {\textrm}{(databases with number 1 and 3})

As  not mentioned other wise equal chances of all the outcomes is assumed so, by the classical definition of probability,

P(The chosen item is a odd numbered database)

=\frac{2}{9}

8 0
3 years ago
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
3 years ago
Homework Progress
Alborosie
I think answer should be c. Please give me brainlest let me know if it’s correct or not okay thanks bye
7 0
3 years ago
Show 3 rows of 2 counters
Julli [10]
C= a counter
c c
c c
c c
3 0
3 years ago
Find the value of x for which the function below is maximum
timurjin [86]

Answer:

x = \frac{1}{2}

Step-by-step explanation:

Given function;

y = 5 + x - x²

To find the maximum value, follow these steps

(i) Find the first derivative (which is the slope) of the given function with respect to x. i.e;

y^{'} = \frac{dy}{dx} = \frac{d(5 + x - x^2)}{dx}

y^{'} = 1 - 2x

(ii) From the result in (i) determine the value of x for which the slope is zero. i.e.

x for which

1 - 2x = 0

=> 1 = 2x

=> x = \frac{1}{2}

Therefore, the value of x for which the function is maximum is \frac{1}{2}

5 0
3 years ago
Read 2 more answers
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