Answer: Which of the following ordered pairs is a solution of the inequality 2x + 6y ≤ 10?a. (3, 1) b. (2, 2) c. (1, 2) d. (1, 0)Answer:The correct answer among the choices is letter d. From the following choices of ordered pair, (1, 0) is the set solution of the inequality 2x + 6y ≤ 10. Substituting the given pair order make the inequality a true statement. To counter check answer, substituting the pair order and solving the linear inequality will result a value to support the correct answer.Step-by-step explanation:a. ( 3,1 ) (x ,y)Substitution2x + 6y ≤ 102(3) + 6(1) ≤ 106 + 6 ≤ 1012 ≤ 10 ( The inequality is False)This is not the correct answer since value to solve for x and y should result to an equal or lesser value than 10.b. (2, 2) (x ,y)Substitution2x + 6y ≤ 102(2) + 6(2) ≤ 104 + 12 ≤ 1016 ≤ 10 ( The inequality is False)This is not the correct answer since value to solve for x and y should result to an equal or lesser value than 10.c. (1, 2) (x ,y)Substitution2x + 6y ≤ 102(1) + 6(2) ≤ 102 + 12 ≤ 1014 ≤ 10 ( The inequality is False)This is not the correct answer since value to solve for x and y should result to an equal or lesser value than 10.d. (1, 0) (x ,y)Substitution2x + 6y ≤ 102(1) + 6(0) ≤ 102 + 0 ≤ 102 ≤ 10 ( The inequality is True)The statement states that 2 is lesser than or equal to 10.
Step-by-step explanation:
Answer:
girl bye you forgot the y coordinate in the first pair sorry lollll
Step-by-step explanation:
U = - 4 i + 1 j
v = 4 i + 1 j
| u | = √ (-4)² + 1² = √ 17
| v | = √4² + 1² = √ 17
| u + v | = √(u + v)²=
= √( u² + 2 u v + v² )= ...
cos ( u, v ) = (-16+1) / (|u| |v|) = -15/17
...= √(17 + 2 · √17 · √17 · ( -15/17) +17) =
= √ 34 - 30 = √ 4 = 2
Answer: C ) 2
