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eimsori [14]
3 years ago
9

3. Open Response Arjun purchased 5 tickets to a play, each with the same price. He was also charged an online service fee of $3.

50 per ticket. Emilia purchased
3 tickets to the same play and paid twice as much for her tickets as Arjun. Emilia was also charged a service fee of $2.75 per ticket. If they spent the same amount, what is the cost of each of the tickets Arjun purchased? Let t represent the cost of each of Arjun’s tickets.


Equation:



Cost of a Ticket:
Mathematics
1 answer:
BartSMP [9]3 years ago
4 0

Answer: I do know I try a lot plz I want the answer

Step-by-step explanation:

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Tìm kiếm x y z<br> x-1/y =1<br> y-1/z =1<br> z-1/x =1
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<em>y</em> - 1/<em>z</em> = 1   ==>   <em>y</em> = 1 + 1/<em>z</em>

<em>z</em> - 1/<em>x</em> = 1   ==>   <em>z</em> = 1 + 1/<em>x</em>

==>   <em>y</em> = 1 + 1/(1 + 1/<em>x</em>) = 1 + <em>x</em>/(<em>x</em> + 1) = (2<em>x</em> + 1)/(<em>x</em> + 1)

<em>x</em> - 1/<em>y</em> = <em>x</em> - (<em>x</em> + 1)/(2<em>x</em> + 1) = (2<em>x</em> ² - 1)/(2<em>x</em> + 1) = 1

==>   2<em>x</em> ² - 1 = 2<em>x</em> + 1

==>   2<em>x</em> ² - 2<em>x</em> - 2 = 0

==>   <em>x</em> ² - <em>x</em> - 1 = 0

==>   <em>x</em> = (1 ± √5)/2

If you start solving for <em>z</em>, then for <em>x</em>, then for <em>y</em>, you would get the same equation as above (with <em>y</em> in place of <em>x</em>), and the same thing happens if you solve for <em>x</em>, then <em>y</em>, then <em>z</em>. So it turns out that <em>x</em> = <em>y</em> = <em>z</em>.

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