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vladimir1956 [14]
3 years ago
8

Help please thanks.... Multiple choice........

Mathematics
1 answer:
AveGali [126]3 years ago
4 0
I wanna say it would be B
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In how many ways can five basketball players be placed in three positions?
Georgia [21]

Answer:

10 ways

Step-by-step explanation:

The number of ways in which five basketball players could be placed in three positions is:

5C_{3} = \frac{5!}{(5-3)!3!}

      = \frac{5!}{3!2!}

      = \frac{5*4*3*2!}{3*2*2!}

      = 5 × 2

     = 10

The basketball players can be arranged in 10 ways.

4 0
3 years ago
20×0.25 decimal operations multiplication<br>​
slavikrds [6]

Answer:

the answer is 5

Step-by-step explanation:

5 0
3 years ago
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What is 82+(12 3+4)-10
Marina86 [1]
Is that 123 or 12 times 3
7 0
3 years ago
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What is the answer to 16&gt; 1.5 + 0.8b
user100 [1]

Answer:

16>2.3b

Step-by-step explanation:

1.5+0.8=2.3

Substitute b as 1. Which would still keep it as 2.3.

8 0
3 years ago
Find S18 for geometric series given a5=-6 and a2= -48
Ganezh [65]

an = a1r^(n-1)

a5 = a1 r^(5-1)

-6 =a1 r^4


a2 = a1 r^(2-1)

-48 = a1 r


divide

-6 =a1 r^4

----------------    yields   1/8 = r^3      take the cube root  or each side

-48 = a1 r                     1/2 = r


an = a1r^(n-1)

an = a1 (1/2)^ (n-1)

-48 = a1 (1/2) ^1

divide by 1/2

-96 = a1


an = -96 (1/2)^ (n-1)


the sum

Sn = a1[(r^n - 1/(r - 1)]

S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]

       =-96 [ (1/2) ^ 17 -1 /-1/2]

      = 192 * [-131071/131072]

 approximately -192

     

       

     

3 0
3 years ago
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