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3 years ago

What is the solution or solutions to 5x-y=-6 and -2x+y=3?

Mathematics

2 answers:

Leya [2.2K]3 years ago

7 0

The answer is x=-1 and y=1. Hope this helps.

sladkih [1.3K]3 years ago

4 0

I would reccomend the app photo math its really easy to use and it answers questions like this.

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91/2 gallons =? quarts

jenyasd209 [6]

the answer is 3648 quarts

5 0

2 years ago

I need help ASAP whit this question

sweet [91]

Answer:

B. 7

Step-by-step explanation:

The original box must be 1 by 1 by 1.

So then the new box would be 2 by 2 by 2.

2×2×2=8

8-1=7

I hope this helps!

pls ❤ and mark brainliest pls!

7 0

2 years ago

Your local bakery offers you a job as a cake maker for an annual salary of $27,300 (source

Svet_ta [14]

If $27,300=one year
$2,275=one month
$568.75=one week

How to get these answers are
27,300/12= 2,275
2,275/4= 568.75 :)

4 0

2 years ago

A pair of $195 boots are discounted 40% If the boots are reduced in price by an additional 66 2/3% what will the discount price

UNO [17]

First, find the 40% discount.
40% of 195 is 78
195 x 0.40 = 78
Subtract that from 195
195 - 78 = 117
Now, find 66 2/3% of 117, since it is an additional reduction after the original discount.
2/3 = 0.667, so 66 2/3% is 66.667%
117 x 0.66667 = 78.00039
And subtract that from 117
117 - 78.00039 = 38.99961, which in dollars would be $38.99. (hundredths, etc. of a cent are usually just dropped; no rounding involved.)
The discount price would then be $38.99

4 0

3 years ago

Read 2 more answers

A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa

g100num [7]

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

$8 \times h + 5 \times f = 24$

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

$6 \times h + 2 \times f = 16.60$

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

5 0

3 years ago