Item 4 Find the median, first quartile, third quartile, and interquartile range of the data. 132,127,106,140,158,135,129,138 med
Ket [755]
Answer:
133.5, 127.5, 139.5, 12
Step-by-step explanation:
order data:
106, 127, 129, 132, 135, 138, 140, 158
Median:
The middle number: (8+1)/2 = 4.5 between the 4&5 numbers
= (135-132)/2= 1.5
1.5 + 132 = 133.5
lower quartile (1st quartile):
(8+1)/4 = 2.25 between the 2&3 numbers
(129+127)/4=0.5
0.5+127 = 127.5
upper quartile(3rd quartile):
(8+1)/4 x3 = 6.75 between the 6&7 numbers
(140-138)/4 x3 = 1.5
1.5 + 138 =139.5
Interquartile range:
139.5-127.5= 12
hope this helps
Answer:
Total Budget: $1200
Step-by-step explanation:
76% = 912
1% = 12
100% = 12 x 100 = $1200
I brute forced till I got the number which multiplied by 76 came out to 912 from there I had what was 1% of the budget then I multiplied that by 100 for the answer.
Answer:
infinite
Step-by-step explanation:
trust me I would know im a smart man in college
Answer:
n=4
Step-by-step explanation:
Of means multiplying so,
×32=24
Multiply by n on both sides to get rid of the n denominator.
3×32=24n
Simplify the equation.
96=24n
Divide by 24.
n= 4
