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My name is Ann [436]
3 years ago
14

PLEASE HELP, YOU WILL GET BRAINLIEST

Mathematics
2 answers:
Anastasy [175]3 years ago
7 0

the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I' is represents the rule

d. (x, y)→(x + 7, y − 7)

I ---> (-8, 4)→(x + 7, y − 7)

I' →(-8 + 7, 4 − 7) = (-1,-3)

really hope that helps

Rom4ik [11]3 years ago
5 0

The answer is (x, y)→(x + 7, y − 7)

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Which is not a classification for AFGH?
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A

Step-by-step explanation:

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3 years ago
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2x - y = 10
Zolol [24]
You can plug -x - 1 for y in the first equation

2x - (-x - 1) = 10

2x + x + 1 = 10

Combine

3x = 9

Divide

x = 3

Plug 3 for x in any equation ( I'll use th second equation )

y = - (3) - 1

y = - 3 - 1 = -4

x = 3 ; y = -4

(3, -4)
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3 years ago
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there are 4 coins. you get a dollar for every head. all four coins are flipped. what is the outcome? what about if you can choos
weqwewe [10]

The outcome for the flip is 2.

Probability:

Probability refer the possibility of the event required.

The probability formula is defined as the possibility of an event to happen is equal to the ratio of the number of favorable outcomes and the total number of outcomes.

Given,

There are 4 coins.

You get a dollar for every head. all four coins are flipped.

To find the outcome of the flips.

The possible outcomes from the initial flip are:

"4 heads" x 1

"3 heads" x 4

"2 heads" x 6

"1 heads" x 4

"0 heads" x 1

This gives an expected return of

=> (4 + 12 + 12 + 4 + 0)/16 = 2

So, the outcome is 2.

Either if you keep it then you have 2 as outcome of the flips, otherwise if you reflip the coins then you will get the same probability for it also.

To know more about Probability here.

brainly.com/question/11234923

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3 0
1 year ago
I need help I’ll give brainliest
galben [10]

Answer:

what the problem?

Step-by-step explanation:

8 0
2 years ago
2. Find the 20th term of an arithmetic sequence if its 6th term is 14 and 14th term is 6.
Fudgin [204]

Answer:

\sf t_{20}= 0

Step-by-step explanation:

<h3>Arithmetic sequence:</h3>

      \sf \boxed{\bf n^{th} \ term = a + (n-1)d}\\\\\text{Here, a is the first term ; d is the common difference }

6th term is 14 ⇒ \sf t_6 = 14

                a + (6 - 1)d = 14

                    a  +  5d = 14  --------------(I)

14th term is 6 ⇒\sf t_{14} = 6

             a + (14-1)d = 6

                  a + 13d = 6 ----------------(II)

Subtract equation (II) from equation(I)

        (I)          a + 5d = 14

        (II)         a + 13d = 6

                    <u>-    -          -</u>

                            -8d = 8

                               d  = 8 ÷(-8)      

                              \sf \boxed{\bf d= (-1)}

Plugin d = -1 in equation (I)

a + 5(-1) = 14

      a -5  = 14

             a = 14 + 5

             \sf \boxed{\bf a = 19}  

20th term:

 \sf t_{20}= 19 + 19*(-1)

       = 19 - 19

   \sf \boxed{\bf t_{20} = 0}

8 0
1 year ago
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