Answer:
I'm not 100% sure but I think it's sunflower
Answer:
25000 fragments
Explanation:
A restriction enzyme can cut a random DNA sequence once per every 4^n where n = number of bases in the recognition site of enzyme.
There are 6 bases in Xbal's recognition site (TCTAGA) so it will cut once per every 4^6 = 4096 bases (4kb).
Total genomic size = 100000kb
So expected number of fragments = Total genomic size/Size of one fragment
= 100000/4
= 25000 fragments
Answer:
analogous structures are similar in function but different structure
Explanation:
this is because they serve the same function.
answer would be D) Cell Plate
