Answer:
−|9| = -9
−|−9| = -9
Step-by-step explanation:
−|9| = -9
|−9| = 9
−|−9| = -9
−(−9) = 9
Answer:
He made 5 2-pointers and 4 3-pointers
Step-by-step explanation:
Let x = number of 2-pointers he scored.
Let y = number of 3 pointers he scored.
The total number of shots he made is x + y, and it it equals 9.
The first equation is
x + y = 9
The total number of points he scored on 2-pointers is 2x. The total number of points he scored on 3-pointers is 3y. The total number of points he scored with 2-pointers and 3-pointers is 2x + 3y. It equals 22.
The second equation is
2x + 3y = 22
We have a system of 2 equations.
x + y = 9
2x + 3y = 22
We will use the substitution method.
Solve the first equation for x.
x = 9 - y
Now substitute 9 - y in for x in the second equation.
2x + 3y = 22
2(9 - y) + 3y = 22
18 - 2y + 3y = 22
y + 18 = 22
y = 4
Now we substitute 4 for y in the first equation and solve for x.
x + y = 9
x + 4 = 9
x = 5
Answer: He made 5 2-pointers and 4 3-pointers
Check:
5 2-pointers and 4 3-popinters are a total of 9 shots, so the number of shots is correct.
Now we check the number of points.
5 * 2 + 4 * 3 = 10 + 12 = 22
22 points is the correct total.
Our answer is correct.
Answer:
56 + 53pi
Step-by-step explanation:
<u><em>Area of small circles:</em></u>
diameter of small circle: 4cm
forumla to find area of circle: A = pir^2
r is radius = half of diameter -> d/2 = 4 / 2 = 2cm
A = pi (2cm)^2
A = pi (4cm)
A = 4pi
<u><em>Area of large circle:</em></u>
diameter of small circle: 4cm
forumla to find area of circle: A = pir^2
r is radius = half of diameter -> d/2 = 14 / 2 = 7cm
A = pi (7cm)^2
A = pi (49cm)
A = 49pi
<u><em>Area of rectangle:</em></u>
Area = width x length
Area = 14cm x 4cm
Area = 56cm
<u><em>Add all three areas:</em></u>
Area of rectangle + large circle + small circle
56cm + 49pi + 4pi = 56cm + 53pi
Answer:
The second choice is the same so it is the last one
Apologies for the bad handwriting.
