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3 years ago

14

What is the square route of pi?

2 answers:

DIA [1.3K]3 years ago

4 0

1.77.......... its a infinite number<span />

Ivanshal [37]3 years ago

3 0

<span>1.7724538509055160272981674833411451827975494561223871282138077898529112845910321813749506567385446654162268236242825706662361528657244226025250937096027870684620376986531051228499251730289508262289320953792679628001746390153514797205167001901852340185854469744949126403139217755259062164054193325009063984076137334774751534336679897893658518364087954511651617387600590673934317913328098548462481849020546548521956132515616474675150427387610561079961271072100603720444836723652966137080943234988316684242138457096091204204277857780686947665700052183056851254133966369446541815107166938833219429293570622688652244205421499480499207564863988748385059306402182140292858112330649789452036211490789622873894032459781985131348712665125062932600446563821096750268124969305954204615607619522173915250702077927580990543329006622230676144696612481887430699788352050614644438541853079735742571791856359597499599522638492422038891039664064472939728413450430021405642334330392617561341763363200170376541634763206692765418128357624903269045084853201341924359897308711937994829387301112625616588188847859778759637613632186342465466413339543557032015226541939521860304973105138294984396591656142459554212266151024785360980955103956007894021880996133828540250168007458027291193664251928205100019363500739146432954934339519288537354592005637665028805405755321231890091263228191509149808366956244831008522219239736463248428632611457669324253715773778944140905445735953512256263910802392369097321279058076171346039145747918797941248502184451458113418888804132209553321846467097274910285652627078454532622278488009823858363007549509547640623770833883572254366215674813276683842449724208745161618332050779914801846668142366936519028454638576148278570377743883762974799827377054315836824109986832285038055263553697222931338052644284103723120439670043076124541383117922782753637155983983768845370278429857070905112238405367790133854145853162080730431380697399874366931660138170792720560419548828580630931116362970478678140269632729627012261359858977545052894831130166840015320748519824024633375558517135680193412289759807195687402505715021417837925436430303659282112509258806189031170745431279039535536606826110011889657420487275939199769955383521150866962555964413705038292449535903106362345305647171162168587254586874400296117579217231905540571986817275884190896496579066965156017283514829038565511698072107953309161308435985243894654406821655003275379960238665037988864815211865799958571865637751133159747535960434137766451191434601342925081163248064090737732126293357474729676793412716029665120809898090577996603051021816255579789074870762110762380262678542970150271091535049853514923908324842808289875955756788488926084208855212695103573702086612591155413204403735608643388371239620642939023786663116326167888419227981949952403942457842204430304204304207109692733929460851049692897391618556078378703364289023429327188729680297215816594261297283663959050411303747457435097490580163269165375769098109748562537785034287994219223771858443183279373129800658703686192301021745450520308455330386195066023643341153205974122426426535421655815003647269194638254412455725947390071922718709796054989724602822602429105077402081237567480762763774370634504631477376948033168357076205874957817335099676287338739670296881906614261445737132282280393544460837760105864673894385577688720397176705927316630090311260814488430862411429224796545402616375515865873519843721755055272950641504357687583814935940105565912150377044197388037056809714346316360543413650766999757621198118425874225208140436406211723091974394552459677817421914643335067146364622594792319497003496602563521033780660380527031652454546473640620830298273494336728477353020224705290099569815670586403988563683495649528828785196447555742560145992685258185630853805815521997029234802948217957003929547687673787467561474545052585171167541520282662279997703869334225001229773162123...</span>

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What is the equation that you get when you put together the two<br> equations below?

yawa3891 [41]

Answer:

1st option

Step-by-step explanation:

Given the 2 equations

2x + 5y = 19 → (1)

y = 3x - 3 → (2)

Substitute y = 3x - 3 into (1)

2x + 5(3x - 3) = 19

5 0

2 years ago

Find an equation of the line that passes through the point (4, 3) and is perpendicular to the line 2x + 9y − 6 = 0.

vesna_86 [32]

Perpendicular has the reciprocal slope and u have to put the point given into point slope.

y-3=9/2(x-4)

(The slope of the original equation was -2/9)

3 0

3 years ago

13.6% complete This is a Single Choice Question; skip ahead to question content A B C D E Confirm Difficulty Level: Moderate Som

Veronika [31]

Answer

about 4 hours and 20 minutes

Step-by-step explanation:

200 divided by 60 is 3.33 or 3 hours and 20 minutes, plus the extra hour

8 0

3 years ago

5 liters of water weighs 11 pounds. A bucket contains 143 pounds of water. How many liters of water are in the bucket

slavikrds [6]

Answer:

65 liters

Step-by-step explanation:

11/5=2.2

143/2.2=65

4 0

3 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago