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3 years ago

12 tickets sold for every 4 tickets not sold if 704 were not sold how many tickets were sold

Mathematics

1 answer:

horsena [70]3 years ago

4 0

there would be 14 tickets

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Explain it so I can better understand it

lorasvet [3.4K]

The question is essentially asking who's equation works better (Part A) and to explain why (Part B).
Marcella is suggesting the equation 6r + 12 = 683.88
Julia is suggesting the equation 6(r + 12) = 683.88

Six people are on the trip.
It is $12 PER person to rent a floatation device.
The total cost of the trip was $683.88.

Hope I've helped!

6 0

3 years ago

What is -3.1 + 2.73

jok3333 [9.3K]

Answer:

-0.37

Step-by-step explanation:

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3 years ago

Consider line 7x+8y=6.

Nata [24]

Answer:

parallel line: -(7/8)

perpendicular line: (8/7)

7x + 8y = 6: y = (3/4) - (7x/8)

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3 years ago

jessy took out a loan of $16,500 over 5 years at 4.2% interest to purchase a new car. how much will she pay in interest on the l

lbvjy [14]

Answer:

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 4.2%/100 = 0.042 per year,

then, solving our equation

I = 16500 × 0.042 × 5 = 3465

I = $ 3,465.00

The simple interest accumulated

on a principal of $ 16,500.00

at a rate of 4.2% per year

for 5 years is $ 3,465.00.

6 0

3 years ago

HELP!! 50 POINTS!!!

aalyn [17]

Step-by-step explanation:

We have been given a table, which represents the projected value of two different houses for three years.

Part A:

$\text{Increase in value of house 1 after one year}=294,580-286,000$

$\text{Increase in value of house 1 after one year}=8580$

$\text{Increase in value of house 1 after two years}=303,417.40-294,580$

$\text{Increase in value of house 1 after two years}=8837.4$

We can see from our given table that the value of house 1 is not increasing at a constant rate, while a linear function has a constant rate of change, therefore, an exponential function can be used to describe the value of the house 1 after a fixed number of years.

$\text{Increase in value of house 2 after one year}=295,000-286,000$

$\text{Increase in value of house 2 after one year}=9,000$

$\text{Increase in value of house 2 after two years}=304,000-295,000$

$\text{Increase in value of house 2 after two years}=9,000$

We can see from our given table that the value of house 2 is increasing at a constant rat that is $9,000 per year. Since a linear function has a constant rate of change, therefore, a linear function can be used to describe the value of the house 2 after a fixed number of years.

Part B:

Let x be the number of years after Dominique bought the house 1.

Since value of house 1 is increasing exponentially, so let us find increase percent of value of house 1.

$\text{Increase }\%=\frac{\text{Final value-Initial value}}{\text{Initial value}}\times 100$

$\text{Increase }\%=\frac{294,580-286,000}{286,000}\times 100$

$\text{Increase }\%=\frac{8580}{286,000}\times 100$

$\text{Increase }\%=0.03\times 100$

$\text{Increase }\%=3$

$\text{Increase }\%=\frac{303,417.40-294,580}{294,580}\times 100$

$\text{Increase }\%=\frac{8837.4}{294,580}\times 100$

$\text{Increase }\%=0.03\times 100$

$\text{Increase }\%=3$

Therefore, the growth rate of house 1's value is 3%.

Since we know that an exponential function is in form: $y=a*b^x$ , where,

a = Initial value,

b = For growth b is in form (1+r), where, r is rate in decimal form.

$3\%=\frac{3}{100}=0.03$

Upon substituting our values in exponential function form we will get,

$f(x)=286,000(1+0.03)^x$ , where, f(x) represents the value of the house 1, in dollars, after x years.

Therefore, the function $f(x)=286,000(1.03)^x$ represents the value of house 1 after x years.

Let x be the number of years after Dominique bought the house 2.

We can see that when Dominique bought house 2 it has a value of $286,000. This means that at x equals 0 value of house will be $286,000 and it will be our y-intercept.

Since value of house 2 is increasing 9000 per year, therefore, slope of our line be 9000.

Upon substituting these values in slope-intercept form of equation $(y=mx+b)$ we will get,

$f(x)=9000x+286,000$ , where, f(x) represents the value of the house 2, in dollars, after x years.

Therefore, the function $f(x)=9000x+286,000$ represents the value of house 2 after x years.

Part C:

Since values in exponential function increases faster than linear function, so the value of house 1 will be greater than value of house 2.

Let us find the value of house 1 and house 2 by substituting x=25 in our both functions.

$f(25)=286,000(1.03)^{25}$

$f(25)=286,000*2.0937779296542148$

$f(25)=598820.48788$

We can see that value of house 1 after 25 years will be approx $598,820.48.

$f(25)=9000*25+286,000$

$f(25)=225,000+286,000$

$f(25)=511,000$

We can see that value of house 2 after 25 years will be approx $511,000.

Since $511,000 is less than $598820.48, therefore, value of house 1 is greater than value of house 2.

6 0

3 years ago

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