Ok first lets take care of the color
given that you have 12 red triangles and the ratio for red triangles to blue triangles is 4:5
if 12=4 than blue=5
12 times 5= 60
12 times 4 = 48
48 red and 60 blue = triangles
48+60=108
there are 108 triangles in total
now since the ratio for triangle square or circle is
for every 3 triangles there are 6 squares and for every six squares there is one circle
t3:s6:c1
since there are 108 triangles
108/3=36
since for every 3 triangles there are 6 squares
six times 36(amount of triangles/3)
6*36+=216
so there are 216 squares
now it says for every six squares there is one circle
therefor (the amount of squares)216/6+= 36
we are back to 36 and there are 36 circles
The simplified value of expression -36/(27/3*2) is -8.
Given an expression -36/(27/3*2).
We are required to find the simplified value of given expression. To simplify the expression we need to use addition,subtraction,multiplication, division, brackets, etc. We can say that we have to use BODMAS in order to find the simplified value of expression.
Expression is combination of numbers, symbols, coefficients, determinants, indeterminants, fraction,algebraic operations,etc. usually not found in equal to form.
The given expression :
=-36/(27/3*2) (Multiplying 3 and 2 first)
=-36/(27/6)
=(-36*2)/9 (Invert the fraction given in denominator)
=-72/9 (Multiplying -36 to 2)
=-8
Hence the simplified value of expression -36/(27/3*2) is -8.
Learn more about expression at brainly.com/question/723406
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Answer:
x = 0
Step-by-step explanation:
Solution :
Consider quadrilateral ABCD is a parallelogram. The parallelogram have diagonals AC and DB.
So in the given quadrilateral ABCD, let the diagonal AC and diagonal DB intersects at a point E.
Thus in the quadrilateral ABCD we see that :
1. AC and DB are the diagonals of quadrilateral ABCD.
2. Angle DCE is congruent to angle BAE and angle CDE is congruent to angle ABE. (they are alternate interior angles)
3. Line DC is congruent to line AB. (opposites sides are congruent in a parallelogram )
4. Angle ABE is congruent to angle CDE. (Angle side angle)
5. Line AE is congruent to line EC. And line DE is congruent to line EB. (CPCTC)
Thus we see that if the diagonals of a 
, then the quadrilateral is a parallelogram.
