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zheka24 [161]
3 years ago
5

A piece of paper is chosen from a bag that contains 10 pieces of paper numbered 1 through 10. Find the probability that the pape

r chosen has an odd number or a number less than 5 on it.
Mathematics
2 answers:
motikmotik3 years ago
7 0

Answer:

1/5

Step-by-step explanation:

Artyom0805 [142]3 years ago
4 0

Answer:

7/10 (70%)

Step-by-step explanation:

There are papers in the bag labeled 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. There are 5 pieces of paper that are odd, which are 1, 3, 5, 7, 9. Then, you also have to add in all the numbers less than 5, which are 1, 2, 3, 4. Now, 1, and 3, are already selected so you need to add 2 and 4. This leaves you with a group of numbers, 1, 2, 3, 4, 5, 7, 9. Those are 7 numbers, out of the possible 10, which means there's a 7/10 chance. (70%) chance.

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Read 2 more answers
Construct a 90% confidence interval for the true mean using the FPCF. (Round your answers to 4 decimal places.) The 90% confiden
mezya [45]

Answer:

The answer is below

Step-by-step explanation:

Twenty-five blood samples were selected by taking every seventh blood sample from racks holding 187 blood samples from the morning draw at a medical center. The white blood count (WBC) was measured using a Coulter Counter Model S. The mean WBC was 8.636 with a standard deviation of 3.9265. (a) Construct a 90% confidence interval for the true mean using the FPCF. (Round your answers to 4 decimal places.) The 90% confidence interval is from to

Answer:

Given:

Mean (μ) = 8.636, standard deviation (σ) = 3.9265, Confidence (C) = 90% = 0.9, sample size (n) = 25

α = 1 - C = 1 - 0.9 = 0.1

α/2 = 0.1/2 = 0.05

From the normal distribution table, The z score of α/2 (0.05) corresponds to the z score of 0.45 (0.5 - 0.05) which is 1.645

The margin of error (E) is given by:

E=z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} }\\ \\E=1.645*\frac{3.9265}{\sqrt{25} }=1.2918

The confidence interval = μ ± E = 8.636 ± 1.2918 = (7.3442, 9.9278)

The 90% confidence interval is from 7.3442 to 9.9278

8 0
4 years ago
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