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2 years ago

Match each whole number with a rational, exponential expression. 1. 512 2. 8 3. 343 4. 216 5. 729 6.

Mathematics

1 answer:

Crazy boy [7]2 years ago

6 0

Answer:

1. 2^9 = 512

2. 2^3 = 8

3. 7^3 = 343

4. 6^3 = 216

5. 3^6 = 729

Step-by-step explanation:

To start we have to express the number as a multiplication of prime numbers, from there we can take the expression as a power

2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 512

2^9 = 512

2 x 2 x 2 = 8

2^3 = 8

7 x 7 x 7 = 343

7^3 = 343

6 x 6 x 6 = 216

6^3 = 216

3 x 3 x 3 x 3 x 3 x 3 = 729

3^6 = 729

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2 years ago

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Answer and Step-by-step explanation: The described right triangle is in the attachment.

As it is shown, AC is the hypotenuse and BC and AB are the sides, so use Pytagorean Theorem to find the unknown measure:

AC² = AB² + BC²

$AB^{2} = AC^{2}-BC^{2}$

$AB =\sqrt{AC^{2}-BC^{2}}$

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$AB =\sqrt{28.75}$

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$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

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