Answer: 16............................
Answer:
Option B.
all real numbers
Step-by-step explanation:
We have
and 
They ask us to find
(fog)(x) and it's Domain
To solve this problem we must introduce the function g(x) within the function f(x)
That is, we must do f(g(x)).
So, we have:


Then:

The domain of the function f(g(x)) is the range of the function
.
Since the domain and range of g(x) are all real numbers then the domain of f(g(x)) are all real numbers
Therefore the correct answer is the option b: 
And his domain is all real.
Harap awak faham hehehe kalau jawapan betul bagi brainliest yer hehehe
Answer:
the lower right matrix is the third correct choice
Step-by-step explanation:
Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).
Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.
__
We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.
The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...
![\left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C1%2B2%261-3%261-1%261000%2829%2B1%29%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C3%26-2%260%2630000%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D)
Already, we see that the second row matches that in the lower right matrix.
The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.
The correct choices here are the two you have selected, and <em>the lower right matrix</em>.
Answer:
The probability that x will take on a value between 120 and 125 is 0.14145
Step-by-step explanation:
For uniform distribution between a & b
Mean, xbar = (a + b)/2
Standard deviation, σ = √((b-a)²/12)
For 110 and 150,
Mean, xbar = (150 + 110)/2 = 130
Standard deviation, σ = √((150-110)²/12 = 11.55
To find the probability that x will take on a value between 120 and 125
We need to standardize 120 & 125
z = (x - xbar)/σ = (120 - 130)/11.55 = - 0.87
z = (x - xbar)/σ = (125 - 130)/11.55 = - 0.43
P(120 < x < 125) = P(-0.87 < x < -0.43)
We'll use data from the normal probability table for these probabilities
P(120 < x < 125) = P(-0.87 < x < -0.43) = P(z ≤ -0.43) - P(z ≤ -0.86) = 0.33360 - 0.19215 = 0.14145
Hope this Helps!!!