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3 years ago

Simplify 2 (csc ^2 0-cot^2 0).

Mathematics

1 answer:

GarryVolchara [31]3 years ago

3 0

Answer:

Step-by-step explanation:

answer is 2 because cosec^2 theta-cot^ theta is 1and when u multiply 1 and 2 answer is 2

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Which decimals written in expanded form are greater than 5.3? Check all that apply. 5 + 0.3 + 0.00 5 + 0.3 + 0.001 (5 × 1) + (2

Ksenya-84 [330]

Answer:

Any number in form of x.y = x (1) + 1/10 (y)

where x = 5 & y > 3 , or x > 5

Step-by-step explanation:

Expanded form of 5.3 = 5 (1) + 3 (1/10)

Some decimals written in expanded form that are greater than 5.3 :

5 (1) + 4 (1/10) = 5.4

6 (1) + 2 (1/10) = 6.2

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3 years ago

The ratio to isabella's money to shane's money is 3:11 if isabella has $33 how much money do shane and isabella have together us

alexgriva [62]

Shane and Isabella have 154 dollars

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3 years ago

Data Entry - No Scoring During your procedure to determine the uncalibrated volume near the stopcock of your buret, what was the

DaniilM [7]

Answer:

0.025 grams

Step-by-step explanation:

The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:

Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)

Volume of drained water = 25 x 10⁻⁶ m³

Density of drained water = 1000 kg/m³

So, for the mass of drained water:

Density of drained water = Mass of drained water/Volume of drained water

Mass of drained water = (Density of drained water)(Volume of drained water)

Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)

<u>Mass of drained water = 0.025 gram</u>

Density

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3 years ago

Isabella averages 152 points per bowling game with a standard deviation of 14.5 points. Suppose Isabella's points per bowling ga

Serga [27]

Answer:

The z-score when x=187 is 2.41. The mean is 187. This z-score tells you that x = 187 is 2.41 standard deviations above the mean.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu = 152, \sigma = 14.5$