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Alchen [17]
3 years ago
7

When a relation is drawn on an xy-plane, what is another name for the set of all x-values from its graph? A. Domain B. Function

C. Output values D. Range
Mathematics
2 answers:
timama [110]3 years ago
6 0
The answer is B........
exis [7]3 years ago
4 0

Answer:

<h2>A. Domain.</h2>

Step-by-step explanation:

An xy-plane is formed by two variables, an independent variable, which is x, and a dependent variable, which is y.

The set that defines the independent variable values for the relation, it's called Domain.

The set that defines the dependent variable values is called Range.

Therefore, in this case, the right asnwer is A. Domain, becase the set of all x-values is actually the Domain set of the relation.

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Chanasia buys a plastic bucket. The bucket weighs 460 g. The label on the bucket says made with 20% recycled plastic. How many g
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92

Step-by-step explanation:

20% of 460 is 92 so it would be 92

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Hey can anyone pls pls pls help me in dis!!!!!
Afina-wow [57]

Answer:

Step-by-step explanation:

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wall is perpendicular to base and ladder is hypotenuse.

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3 years ago
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Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!
kupik [55]

Answer:

The equation of required line is: \mathbf{5x-8y+34=0}

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to 5x-8y+12=0 and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line  5x-8y+12=0 to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: y=mx+b where m is slope.

5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}

So, the slope m = 5/8

The slope of required line is m=\frac{5}{8}

Now finding y-intercept using slope m=\frac{5}{8} and point(-2,3)

y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}

So, the equation of required line having slope m=\frac{5}{8}  and y-intercept b=\frac{17}{4}

y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8}  \\8y=5x+34\\5x-8y+34=0

So, The equation of required line is: \mathbf{5x-8y+34=0}

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2 years ago
Quadrilateral ABCD is a square. BC = 10 What is the length of AC? A. 10 sqrt 2 B. 20 sqrt 3 C. 10 sqrt 3 D. Sqrt 100
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A is the correct answer to this question because AC and BC differ because the B must be changed to an A.

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