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lys-0071 [83]
3 years ago
7

Find the matrix A of the linear transformation T(f(t))= 4f'(t)+6f(t) from P2 T0 P2 with respect to the standard basis of P2 {1,t

,t^2}
You don't need to answer the full question i have the answer just tips on where to start and on what to do would be nice.
Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0

Answer:  The required matrix is

A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .

Step-by-step explanation:  The given linear transformation is

T(f(t)) = 4f'(t) + 6f(t).

We are to find the matrix A of T from P² to P² with respect to the standard basis P² = {1, t, t²}.

We have

T(1)=4\times\dfrac{d}{dt}1+6\times1=0+6=6\times 1+0\times t+0\times t^2,\\\\T(t)=4\times\dfrac{d}{dt}t+6\times t=4+6t=4\times1+6\times t+0\times t^2,\\\\T(t^2)=4\times\dfrac{d}{dt}t^2+6\timest^2=8t+6t^2=0\times 1+8\times t+6\times t^2.

Therefore, the matrix A is given by

A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .

Thus, the required matrix is

A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .

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The answer is 30720

A = P * rⁿ
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r - the growth rate
P - the initial number of bacteria
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We know:
A = ?
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P = 15
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After 11 hours
A(11) = 15 * 2¹²
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After 12 hours
A(12) = 15 * 2¹²
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A(12) = 61440

<span>How many bacteria are grown during the 12th hour?
A(12) - A(11) = 61440 - 30720 = 30720</span>
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Answer:

See below.

Step-by-step explanation:

2x^2 - 2x - 12 = 0

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