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OLga [1]
3 years ago
10

Please help due soon!!!!!

Mathematics
1 answer:
eimsori [14]3 years ago
7 0

First you need to graph the coordinate points to see the triangle.

Then you need to drop lines down on the graph to form right triangles and use Pythagorean Theorem.

The line of points -5,-1 and -2,3 measures 5 using Pythagorean theorem.

The line of points 6,-3 and -5,1 measures √125

The line of points 6,-3 and -2,3 measures 10 using Pythagorean theorem.

So...

5 + 10 = 15

15 + √125

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I am in need of help :) please and thank you :):
nika2105 [10]
It’s the second answer
8 0
3 years ago
Read 2 more answers
The disk enclosed by the circle x+y = 4 is revoived about the y-axis to generate solid sphere. A hele of diameter 2 units is the
Vesnalui [34]

Step-by-step explanation:

Suppose we have a curve, y = f(x).

y = f(x)

x = a x = b

Imagine that the part of the curve between the ordinates x = a and x = b is rotated about the

x-axis through 360◦

. The curve would then map out the surface of a solid as it rotated. Such

solids are called solids of revolution. Thus if the curve was a circle, we would obtain the surface

of a sphere. If the curve was a straight line through the origin, we would obtain the surface of

a cone. Now we already know what the formulae for the volumes of a sphere and a cone are,

but where did they come from? How can they calculated? If we could find a general method

for calculating the volumes of the solids of revolution then we would be able to calculate, for

example, the volume of a sphere and the volume of a cone, as well as the volumes of more

complex solids.

To see how to carry out these calculations we look first at the curve, together with the solid it

maps out when rotated through 360◦

.

y = f(x)

Now if we take a cross-section of the solid, parallel to the y-axis, this cross-section will be a

circle. But rather than take a cross-section, let us take a thin disc of thickness δx, with the face

of the disc nearest the y-axis at a distance x from the origin.

www.mathcentre.ac.uk 2

6 0
3 years ago
Use slopes and y-intercepts to determine if the lines 6x+y=−1 and −2x−5y=1 are parallel.
kobusy [5.1K]

Answer:

The two lines are not parallel.

Step-by-step explanation:

Every linear equation follows this structure:

y = mx + b

y is the y value

x is the x value

m is the gradient/slope of the line

b (or sometimes c) is the y-intercept of the line

Firstly, we have to get the y term on one side by itself.

6x + y = -1

-6x        -6x

y = -6x - 1

-2x -5y = 1

+2x         +2x

-5y = 2x + 1

Secondly, we make it so the y term is just the y value.

The first equation is already like this, so we don't need to do anything to that.

-5y = 2x + 1

÷ -5  ÷ -5

y = (2x + 1) / -5

This can be expanded and simplified to:

y = -2/5x - 1/5

Thirdly, we have to compare the slopes and y-intercepts.

y = -6x - 1

y = 2/5x - 1/5

If the slopes are the same and the y-intercepts are different, they are parallel. However, the slopes are different, therefore they are not parallel.

7 0
3 years ago
What is the value of F(x)=3x-12forx=9?
GrogVix [38]

Answer:

15

Step-by-step explanation:

3(9)=27

27-12=15

7 0
3 years ago
Find the coordinates of the midpoint of a line segment with end points (-3,4) and (7,9)
lesantik [10]

Answer:  (2, 6.5)

<u>Step-by-step explanation:</u>

Midpoint_{x,y}=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad \quad=\bigg(\dfrac{-3+7}{2},\dfrac{4+9}{2}\bigg)\\\\\\.\qquad \qquad \quad=\bigg(\dfrac{4}{2},\dfrac{13}{2}\bigg)\\\\\\.\qquad \qquad \quad=\large\boxed{(2,6.5)}

6 0
3 years ago
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